Question

Show all work and answer all 4 parts. Projectile motion. 20 points. Thank you.

Answer 1

Answer:

i took g = 9.8m/s

A. 1.16secs

B. 2.32secs

C. 6.57m

D. 57.91m

Explanation:

A. How long does the Missile take to reach ot peak?

Time taken (t) =( U²Sin (angle) )/g

u = initial velocity = 25m/s

angle given = 30°

g = acceleration due to gravity = 9.8m/s²

t = U² x Sin (angle) / g

t = 25² x Sin(30)/9.8

t = 1.61secs

B. How long is the missile in the air in total?

T = 2t

T = 2 x 1.61 = 2.32 secs

C. what maximum Height does the missile reach?

• Maximum height = U²Sin²(angle) / 2g
• M.H =25² x Sin(30)² / 2 x 9.8
• M.H=6.57m
• Maximum height= 6.57m

D. How far does the missile travel Horizontally?

• Range = U²2Sin(angle)/g
• Range = 25² x 2 x Sin(30) / 9.8
• Range = 57.91m