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fenix001 [56]
3 years ago
13

If PEs represents the potential energy stored in a spring at kg times m/s sqaured, and x represents the change in spring length

from its equilbrium position in m, what is the unit for the spring constant k in the formula PEs=1/2kx squared?
Physics
1 answer:
miss Akunina [59]3 years ago
4 0
 PE = 1/2 . k . x^2 = kg . m^2 / s^2 

Forget the 1/2 , it has no units 

<span>k = kg . m^2 / s^2 / m^2 = kg / s^2 

Therefore, the unit of the spring constant k would be  </span><span>kg / s^2.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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4 years ago
If the density of a diamond is 3.5 /cm^ 3 what would be the mass of a diamond whose volume is 0.5 cm ^ 3 ?
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Answer:

1.75g

Explanation:

Given parameters:

Density  = 3.5g/cm³

Volume  = 0.5cm³  

Unknown:

Mass of the diamond  = ?

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Density is the mass per unit volume of a substance

  Density  = \frac{mass}{volume}  

So;

  Mass  = 3.5 x 0.5  = 1.75g

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An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i
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Answer:5 m/s^{2}

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

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Then, isolating g and taking into account sin(90\°)=1:

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Finally:

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

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