Answer:
A
Explanation:
Enjoyed for many years or decades.
Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
Answer: 1/R = 1/r1 + 1/r2 + 1/r3
Explanation:
Just did the test myself. Hope this helps!
Wave speed = frequency (in Hz) x wavelength (in m) so wave speed = 11 x 0.011 = 0.121 m/s
Sphere A travels a horizontal distance of (10 m/s) <em>t</em> after time <em>t</em>, while sphere B travels a distance of (5 m/s) <em>t</em>. So sphere B lands on the floor some point between the table's edge and the point X (A).