One cubic foot of water can store 312btu. a home requires 100,000 what is the volume
1 answer:
Volume of water required to store 100,000 Btu of thermal energy is .
<u>Explanation:</u>
The complete question is : One cubic foot of water can store 312 Btu of thermal energy. On a cold winter day a well-constructed home may require 100,000 Btu of nighttime space heating. What is the volume of water required to store this energy? In this question , it's given that One cubic foot of water can store 312 Btu of thermal energy or 312 Btu takes 1 cubic foot of water ,So
1 Btu takes cubic foot of water
Therefore, 100,000 Btu takes:
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∴ Volume of water required to store 100,000 Btu of thermal energy is .
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I attached the picture of the missing table.
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
Total velocity is:
Once we calculate velocities we get:
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
Total velocity is:
Once we calculate velocities we get:
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing
Explanation:
Given that,
Radius R= 2.00
Charge = 6.88 μC
Inner radius = 4.00 cm
Outer radius = 5.00 cm
Charge = -2.96 μC
We need to calculate the electric field
Using formula of electric field
(a). For, r = 1.00 cm
Here, r<R
So, E = 0
The electric field does not exist inside the sphere.
(b). For, r = 3.00 cm
Here, r >R
The electric field is
Put the value into the formula
The electric field outside the solid conducting sphere and the direction is towards sphere.
(c). For, r = 4.50 cm
Here, r lies between R₁ and R₂.
So, E = 0
The electric field does not exist inside the conducting material
(d). For, r = 7.00 cm
The electric field is
Put the value into the formula
The electric field outside the solid conducting sphere and direction is away of solid sphere.
Hence, This is the required solution.