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4 years ago

Can I get a little help on the problem?

1 answer:

6 0

This question explores something known as exponential growth, and is often used to determine compound interest after a period of time.

We can use equation

y = xr^n

Where y is the value after n years, x is the initial value and r is the percentage growth each year.

By substituting

1462 * 1.03^10

We get a value that rounds to 1965, so your answer is D.

I suggest you look at exponential growth and decay on khanacademy, they explain it very well!

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22. A question bank has questions of Physics and

trasher [3.6K]

Step-by-step explanation:

Let the number of books of Physics be x . Then , No. of chemistry books =3.5x

Now , according to question :

x+3.5x=90

Or , 4.5x=90

Or , x=90/4.5

Or , x=20

Now ,

3.5x= 3.5×20

= 70

Therefore , there were 70 chemistry books and 20 physics books in that question bank.

7 0

3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

puteri [66]

Answer:

a) σ_95% = [ ± 0.09934 ]

b) Increase the number of samples taken from each clinic and find their average over course of months for the entire year.

Step-by-step explanation:

Solution:-

- The data from the health provider for the number of CAT scans performed in a month in its clinics.

- The reported variable "X" : number of CAT scans each month expressed as the number of CAT scans per thousand members of the health plan.

- The statistical results were obtained as follows:

2.31, 2.09, 2.36, 1.95, 1.98, 2.25, 2.16, 2.07, 1.88, 1.94, 1.97,2.02

- We see that a samples were taken from n = 12 clinics were taken. The sample mean ( x_bar ) can be calculated from the following descriptive stats formula:

$x_b_a_r = \frac{Sum ( x_i )}{n}\\\\x_b_a_r=\frac{2.31+2.09+2.36+1.95+1.98+2.25+2.16+2.07+1.88+1.94+1.97+2.02}{12}\\\\x_b_a_r=\frac{24.98}{12}\\\\x_b_a_r=2.0817\\$

- Similarly, we will compute the sample standard deviation ( s ) ( Normally distributed population ) for unknown population standard deviation ( σ ), the following formula is used:

$s = \sqrt{\frac{Sum (x_i - x_b_a_r)^2}{n-1} } \\\\Sum (x_i - x_b_a_r)^2 = (2.31 - 2.0817)^2 + (2.09 - 2.0817)^2 + (2.36 - 2.0817)^2 + (1.95 -\\\\2.0817)^2 + (1.98 - 2.0817)^2+ (2.25 - 2.0817)^2+ (2.16 - 2.0817)^2 + (2.07 - 2.0817)^2\\\\(1.88 - 2.0817)^2 + (1.94 - 2.0817)^2 + (1.97 - 2.0817)^2 + (2.02 - 2.0817)^2\\\\= 0.26896668\\\\\\s = \sqrt{\frac{0.26896668}{12-1} } = 0.15636$

- We have two parameters ( x_bar and s ) for the approximated normal distribution of random variable X with unknown population:

x_bar = 2.0817

s = 0.15636

- The sample size n = 12 ≤ 30 and unknown population standard deviation standard normal distribution is not applicable. In such case we use t-distributions for test statistics and rejection criteria.

degree of freedom = n - 1 = 12 - 1 = 11

CI (two sided ) = 95%

Significance Level (α) = 1 - CI = 1-0.95 = 0.05

- To determine the t-critical value defined by the significance level of two sided test we have:

t-critical = t_α/2 = t _ 0.025

t-critical = t _ 0.025 = ±2.201

- We will now construct a 95% confidence interval for the population standard deviation ( σ ).

σ_95% = [ -t-critical * ( s / √n ) , t-critical * ( s / √n ) ]

σ_95% = [ -2.201 * ( 0.15636 / √12 ) , 2.201 * ( 0.15636 / √12 ) ]

σ_95% = [ ± 0.09934 ]

- To address any reservation to the standard error in standard deviation can be curtailed by increasing the sample size ( n ) at-least enough for the distribution "X" to assume standard normality. n ≥ 30

4 0

3 years ago

Jose is training for a cross country ATV race. The ratio of the riding part to the climbing part is 2:9 . If he wants to train u

saveliy_v [14]

84 / 2 = 42 so 42 × 9 = 378

6 0

4 years ago

What are the center and radius of the circle defined by the equation ?

RUDIKE [14]

You didn't give us the equation, but circle equations are in the form;
(x-h)^2 + (y-k)^2 =r^2 where h and k are the x and y coordinate of the center and r is the radius of the circle squared.

7 0

3 years ago

A paintball court charges an initial entrance fee plus a fixed price per ball.

m_a_m_a [10]

Answer : The cost of 10 balls will be, 13.5 dollars

Step-by-step explanation :

As we are given the following expression:

$P=0.80\times n+5.50$