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Morgarella [4.7K]
3 years ago
14

From the same height and at the same time one ball is dropped and another ball is fired horizontally which ball has the greater

magnitude
Physics
1 answer:
Pani-rosa [81]3 years ago
7 0
The ball thrown horizontally
The weight of the ball dropped down is a factor in magnitude with gravity playing an important role as well.
On the other hand, the ball thrown horizontally has speed which allows magnitude and gravity playing against it, eventually the ball will hit the ground harder than the one dropped straight down
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An atom has an atomic number of 12 and a mass amber of 25. How many neutrons does the stom have? (1 point)
Alisiya [41]

Answer:

23423421342

Explanation:

342342342

7 0
3 years ago
Which device converts chemical energy directly into electrical energy?
Molodets [167]

Answer:

A

Explanation:

Name me brainliest plzzzzz

4 0
3 years ago
Read 2 more answers
Resistance and resistivity are related by a: 1.factor that is dependent on the length of the material 2.factor that is dependent
luda_lava [24]

Answer:

1. factor that is dependent on the length of the material.

2. factor that is dependent on the area of the material

Explanation:

Resistance R is directly proportional to its length L of an object and it is inversely proportional to the crossectional area of that object.

Mathematically, this is represented as:

a) Resistance R is directly proportional to its length L of an object

R ∝ L ......... Equation 1

b) Resistance R is inversely proportional to the crossectional area (A) of an object

R ∝ 1/A ............ Equation 2

Combining the two equations together, we have:

Resistance R is directly proportional to its length L of an object

R ∝ L/A .......... Equation 3

Resistivity of a material is the natural or inherent or intrinsic property that a material has. The Resistivity of a material is not dependent on the length or crossectional area of such material. It is only temperature dependent.

The resistance of a material is also dependent on the resistivity of the material. This means the resistance of a material is directly proportional to the resistivity of the material.

R ∝ ρ........Equation 4

Combining Equation 4 and 3 together, we have:

R = ρL/A

Where:

R = Resistance

ρ = Resistivity

L = Length of the material

A = Crossectional area of the material

Resistance and resistivity are related by a factor that is dependent on the length of the material a factor that is dependent on the area of the material

3 0
4 years ago
HELPPP ASAP!!!!!!
fomenos

Answer:

The acceleration of the player is - 4.9 m/s²

Explanation:

The given is:

1. The mass of the player is 55 kg

2. His initial speed is 4.6 m/s

3. The coefficient of the kinetic fraction between the player and the

    ground is 0.50

We need to find the player acceleration

According to Newton's Law

→ ∑ forces in direction of motion = mass × acceleration

There is only the friction force opposite to the motion

→ Friction force = μR

where μ is the coefficient of friction and R is the normal reaction

→ The normal reaction R = mg

where m is the mass and g is the acceleration of gravity

→ m = 55 kg , g = 9.8 m/s²

→ R = 55 × 9.8 = 539 N

→ ∑ F = - μR

→ - μR = m × a

→ μ = 0.5 , R = 539 N , m = 55

→ -(0.5)(539) = 55 × a

→ - 269.5 = 55 a

Divide both sides by 55

→ a = - 4.9 m/s²

The acceleration of the player is - 4.9 m/s²

Learn more:

You can learn more about Newton's law in brainly.com/question/11911194

#LearnwithBrainly

3 0
4 years ago
Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
4vir4ik [10]

The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance D_{A} beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed v_{A}. Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed v_{B}, which is greater than v_{A}.

Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.

Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

Answer: Part A: t=\frac{D_{A}}{v_{B}-v_{A}}

              Part B: x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Explanation: First, let's write an equation of motion for each car.

Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:

x=x_{0}+vt

where

x_{0} is initial position

v is velocity

t is time

Car A started the race at a distance. So at t = 0, initial position is D_{A}.

The equation will be:

x_{A}=D_{A}+v_{A}t

Car B started at the starting line. So, its equation is

x_{B}=v_{B}t

Part A: When they meet, both car are at "the same position":

D_{A}+v_{A}t=v_{B}t

v_{B}t-v_{A}t=D_{A}

t(v_{B}-v_{A})=D_{A}

t=\frac{D_{A}}{v_{B}-v_{A}}

Car B meet with Car A after t=\frac{D_{A}}{v_{B}-v_{A}} units of time.

Part B: With the meeting time, we can determine the position they will be:

x_{B}=v_{B}(\frac{D_{A}}{v_{B}-v_{A}} )

x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Since Car B started at the starting line, the distance Car B will be when it passes Car A is x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}} units of distance.

5 0
3 years ago
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