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bixtya [17]
3 years ago
7

How much force is required to accelerate a 0.10 gram mosquito at 20m/?

Physics
2 answers:
EastWind [94]3 years ago
8 0

Answer:  0.002 newtons

===================================================

Work Shown:

I'm assuming you meant to write "at 20 m/s^2" at the end. If so, then,

0.10 grams = 0.10/1000 = 0.0001 kg

m = 0.0001 kg = mass

a = 20 m/s^2 = acceleration

F = ma .... newton's second law

F = 0.0001*20

F = 0.002

The force required is 0.002 newtons

uysha [10]3 years ago
6 0

Answer:Force is 2

Explanation:

F=ma

F= 0.10x20

F=2

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Answer:

(a). The path length is 3.09 m at 30°.

(b). The path length is 188.4 m at 30 rad.

(c). The path length is 1111.5 m at 30 rev.

Explanation:

Given that,

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Using formula of path length

Path\ length =angle\times radius

Path\ length=0.523\times5.9

Path\ length =3.09\ m

(b). Angle = 30 rad

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Path\ length=30\times5.9

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(c). Angle = 30 rev

We need to calculate the angle in rad

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\theta=188.4\ rad

We need to calculate the path length

Path\ length=188.4\times5.9

Path\ length =1111.56\ m

Hence, (a). The path length is 3.09 m at 30°.

(b). The path length is 188.4 m at 30 rad.

(c). The path length is 1111.5 m at 30 rev.

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