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3 years ago

A boy of mass, m weights 895 N. What is his mass, m?

Physics

1 answer:

Ksju [112]3 years ago

6 0

Answer:

91.3 kg

Explanation:

weight = m*g

m: mass

g: gravity = 9.8 or 10 (depends on what your instructor tells you to use)

mass = w/g

895/9.8 = 91.3 KG

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What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes th

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Answer:

its D

Explanation:

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2 years ago

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What do executive departments do?

enot [183]

Answer:

Image result for What do executive departments do?

Under Article II of the Constitution, the President is responsible for the execution and enforcement of laws created by Congress. Fifteen executive departments—each led by an appointed member of the President's Cabinet—carry out the day-to-day administration of the Federal Government.

Explanation:

The Cabinet and independent federal agencies are responsible for the day-to-day enforcement and administration of federal laws. ... Fifteen executive departments — each led by an appointed member of the President's Cabinet — carry out the day-to-day administration of the federal government.

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2 years ago

The horizontal beam in Fig. E11.14 weighs 190 N, and its center of gravity is at its center. Find (a) the tension in the cable a

grandymaker [24]

Answer:

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

Weight of beam= 190 N

Here, The center of gravity is at its center

According to figure,

The angle is

$\sin\theta=\dfrac{3}{5}$

The horizontal component is

$T_{x}=T\cos\theta$

The vertical component is

$T_{y}=T\sin\theta$

(a). We need to calculate the tension in the cable

Using formula of net torque acting on the pivot

$\sum\tau=F_{b}\times r+F_{w}\times r'-T\sin \theta\times r'$

Put the value into the formula

$0=190\times2+300\times 4-T\sin\theta\times 4$

$T\sin\theta\times 4=380+1200$

$T=\dfrac{1580\times5}{3\times 4}$

$T=658.33\ N$

(b). We need to calculate the horizontal components of the force exerted on the beam at the wall

Using formula of horizontal component

$F_{x}=T\cos\theta$

Put the value into the formula

$F_{x}=658.33\times\dfrac{4}{5}$

$F_{x}=526.66\ N$

(c). We need to calculate the vertical components of the force exerted on the beam at the wall

Using formula of vertical component

$F_{y}=F_{b}+F_{w}-T\sin\theta$

Put the value into the formula

$F_{y}=190+300-658.33\times\dfrac{3}{5}$

$F_{y}=95.002\ N$

Hence, (a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

3 0

3 years ago

Two north magnets will do this

DerKrebs [107]

Answer:

Repel one another

Explanation

I am assuming you meant "two north poles will do this" Or something similar.

because you can't isolate poles, so a magnet wouldn't be just north

ANYWAYS i say repel because like terms repel, opposites attract.

5 0

2 years ago

A skater with a mass of 72 kg is traveling east at 5.8 m/s when he collides with another skater of mass 45 kg heading 60° south

Akimi4 [234]

The final velocity is 5.87 m/s

<u>Explanation:</u>

Given-

mass, $m_{1}$ = 72 kg

speed, $v_{1}$ = 5.8 m/s

$Mass_{2}$ , $m_{2}$ = 45 kg

$speed_{2}$ , $v_{2}$ = 12 m/s

Θ = 60°

Final velocity, v = ?

Applying the conservation of momentum:

$m_{1}$ X $v_{1}$ + $m_{2}$ X $v_{2}$ = ( $m_{1}$ + $m_{2}$ ) v

72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v

v = 417.6 + 540 X $\frac{0.5}{117}$

v = 417.6 + $\frac{270}{117}$

v = 5.87 m/s

The final velocity is 5.87 m/s

8 0

3 years ago