All categories

3 years ago

A boy of mass, m weights 895 N. What is his mass, m?

Physics

1 answer:

Ksju [112]3 years ago

6 0

Answer:

91.3 kg

Explanation:

weight = m*g

m: mass

g: gravity = 9.8 or 10 (depends on what your instructor tells you to use)

mass = w/g

895/9.8 = 91.3 KG

You might be interested in

Plz help!!!

shtirl [24]

Answer:

I think the answer to your question is true

3 0

3 years ago

A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it

fomenos

Answer:68.15m/s

Explanation:

Given:

v₁=15m/s

a=6.5m/s²

v₁=?

x=340m

Formula:

v₁²=v₁²+2a (x)

Set up:

= $\sqrt{15m/s} ^{2} +2(6.5m/s^2)(340m)$

<h2>Solution:</h2><h2>68.15m/s</h2>

6 0

3 years ago

Which is a possible disadvantage of using flowing water to produce electricity?

Anastasy [175]

Drought
....................

3 0

3 years ago

If it requires 2.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re

valina [46]

Answer:

16 J

Explanation:

It is given that,

Work done, W = 2 J

A spring is stretched by 2.0 cm from its equilibrium length

We need to find how much more work will be required to stretch it an additional 4.0 cm.

Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :

$U=\dfrac{1}{2}kx^2\\\\k=\dfrac{2U}{x^2}\\\\k=\dfrac{2(2)}{(0.02)^2}\\\\k=10000\ N/m$

The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.

$W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 10000\times ((0.06)^2-(0.02)^2)\\\\W=16\ J$

So, the required work done is 16 J.

7 0

3 years ago

Which of the following statements explains how total time spent in the air is affected as a projectile's angle of launch is incr

charle [14.2K]

Answer:

Therefore letter C is the correct answer.

Explanation:

In a projectile motion the total time in the air can be calculated using the following equation:

We analyze the y-component motion.

$v_{fy}=v_{iy}-gt$

When the final velocity (v(f)) is equal to zero we calculate the upward time and multiplying it by 2 we find the total time in the air. So we will have:

$t_{tot}=2\frac{v_{iy}}{g}$

$t_{tot}=2\frac{v_{i}sin(\theta)}{g}$

We can see that the total time is directly proportional to the angle, then when θ increase t increase.

Therefore letter C is the correct answer.

I hope it helps you!

3 0

3 years ago