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postnew [5]
3 years ago
5

What is the osmotic pressure of a .25 M solution of NaCl at 25 degrees Celsius?

Chemistry
1 answer:
Ilya [14]3 years ago
3 0

Answer:

6.113 atm

Explanation:

Data provided in the question:

Molarity of the solution = 0.25 M

Temperature, T = 25° C = 25 + 273 = 298 K

Now,

Osmotic pressure (π) is given as:

π = MRT

where,

M is the molarity of the solution

R is the ideal gas constant = 0.082057 L atm mol⁻¹K⁻¹

on substituting the respective values, we get

π = 0.25 × 0.082057 × 298

or

π = 6.113 atm

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Answer:

Option B. 25mL

Explanation:

Step 1:

Data obtained from the question:

Molarity of stock solution (M1) = 6M

Volume of stock solution needed (V1) =..?

Molarity of the diluted solution (M2) = 0.5M

Volume of diluted solution (V2) = 300mL

Step 2:

Determination of the volume of the stock solution needed.

Using the dilution formula, we can easily find the volume of the stock solution needed as follow:

M1V1 = M2V2

6 x V1 = 0.5 x 300

Divide both side by 6

V1 = (0.5 x 300) /6

V1 = 25mL

Therefore, 25mL of 6M NaOH is needed.

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