Volume of NaOH required to react = 145.5 ml
<h3>Further explanation</h3>
Reaction
CO₂(g)
+ 2 NaOH(aq) ⇒Na₂CO₃(aq) + H₂O(l)
The volume of CO₂ : 0.45 L
mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

Then volume of NaOH :

Answer:
D. 45.0 g
Explanation:
In present reaction, 1 mol of N2 react with 3 moles of H2 to generate 2 moles of NH3
Thus, 2 moles of NH3 ≡ 3 moles of H2
Therefore, 15 moles of NH3 ≡ (3×15)/2 = 22.5 moles of H2.
We know that, 1 mole of H2 ≡ 2 g
Therefore, 22.5 moles of H2 ≡ 2 × 22.5 = 45 g
Thus, 45 g of hydrogen are needed to produce 15.0 mol of ammonia, if the reaction goes to completion
You can separate out the canola oil easily, because it has cooled down enough to turn back into a solid.
It means to change, and form means shape. So to transform is to change shape.