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3 years ago

A new pesticide has been introduced to the habitat of this population of beetles.

Chemistry

2 answers:

lys-0071 [83]3 years ago

7 0

Answer:

The correct answer is "decreased genetic variation".

Explanation:

By introducing a new pesticide into the habitat of a beetle population what happens is that there will be a decrease in the genetic variation in this population. This is due to the harmful effect that pesticides have on insects and other living beings.

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yuradex [85]3 years ago

5 0

Answer:

decreased genetic variation ( first choice)

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using the symbol M for the element, write the chemical formula for the compound that forms when element M reacts with iodine.

Anon25 [30]

Answer : The chemical formula for the compound is, $MI$

Explanation :

When the element 'M' react with the $I_2$ to give $MI$ .

The balanced chemical reaction is,

$2M+I_2\rightarrow 2MI$

In this reaction, 'M' is in mono-atomic form and $I_2$ is in diatomic form.

By the stoichiometry,

2 moles 'M' react with the 1 mole of $I_2$ to give 2 moles of $MI$ .

Therefore, the chemical formula of the compound is, $MI$

6 0

3 years ago

Read 2 more answers

A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0

miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

$Q_{metal} - Q_{water} = 0$

$Q_{metal} = Q_{water}$

Where:

$Q_{water}$ - Heat received by water, measured in joules.

$Q_{metal}$ - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

$m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})$

The specific heat of the metal is cleared within equation above:

$c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}$

If we know that $m_{water} = 0.237\,kg$ , $m_{metal} = 0.244\,kg$ , $c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}$ , $T_{w,o} = 10\,^{\circ}C$ , $T_{m,o} = 100.10\,^{\circ}C$ and $T = 15.30\,^{\circ}C$ , the specific heat of molybdenum is:

$c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}$