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3 years ago

A weak electrolyte exists predominantly as __________ in solution.

1 answer:

4 0

A weak electrolyte exists predominantly as molecules in solution. Electrolytes are substances that have the ability to turn into ions when placed in water. The resulting aqueous solution then has the ability to conduct electricity due to the presence of ions. Strong electrolytes are those that readily breakdown into ions while weak electrolytes only partially dissolve into ions and thus mostly exists as molecules.

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A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 23.0 mL of

Rus_ich [418]

52.0ml of 0.35M CH3COOH : 0.052 L(0.35M) = .0182 mol of CH3COOH.

31.0ml of 0.40M NaOH : .031 L(0.40M) = .0124 mol of NaOH.

After the reaction, .0124 Mol CH3COO- is generated and .058 mol CH3COOH is left un-reacted. The concentration would be 12.4/V and 5.8/V, respectively. Therefore:


pH = -log([H+]) = -log(Ka*[CH3COOH]/[CH3COO-]) 
= -log(1.8x10^-5*5.8/12.4) = 5.07

6 0

3 years ago

What is the frequency of an X-ray that has a wavelength of 1.5 x 10 -9 m? The speed of electromagnetic radiation is 3.0 x 10 8 m

AlexFokin [52]

Answer:

2.0x10¹⁷ Hz is the frequency of the X-ray

Explanation:

We can find the frequency of a wave of energy from the wavelenght and its speed using the formula:

v = λƒ

Where v is speed (For electromagnetic radiation = 3.0x10⁸m/s)

λ is the wavelength in meters = 1.5x10⁻⁹m

And f is the frequency in s⁻¹ = Hz

Replacing:

3.0x10⁸m/s = 1.5x10⁻⁹m*ƒ

3.0x10⁸m/s / 1.5x10⁻⁹m = f

f =

<h3>2.0x10¹⁷ Hz is the frequency of the X-ray</h3>

3 0

3 years ago

Suggest a method for measuring the size of the colony.

Evgen [1.6K]

Answer:

Counting the number of colonies that arise on a pour plate can calculate the concentration by multiplying the count by the volume spread on the pour plate. Direct counting methods are easy to perform and do not require highly specialized equipment, but are often slower than other methods

Explanation:

I hope it will help you

7 0

3 years ago

Complete combustion of 3.20g of a hydrocarbon produced 9.69g of CO2 and 4.96g of H2O. What is the empirical formula for the hydr

vlabodo [156]

Let empirical formula for hydrocarbon is CxHy

it will undergo combustion as

CxHy + (x + y/4) O2 ---> xCO2 + (y/2 )H2O

Given that mass of CO2 produced = 9.69 g

So moles of CO2 produced = 9.69 / 44 = 0.22 moles

So moles of carbon present = 0.22 moles

mass of H2O produced = 4.96 g

Moles of H2O produced = mass / molar mass = 4.96 / 18 = 0.28 moles

So moles of H present = 2 X 0.28 = 0.56 moles

Let us divided the moles of each with lowest value of moles

Moles of Carbon = 0.22 / 0.22 = 1 moles

moles of H = 0.56 / 0.22 = 2.55

Multiplying with two to get whole number

the ratio of carbon and hydrogen will be : C:H = 2:5

empirical formula : C2H5

4 0

3 years ago

Read 2 more answers

The temperature of a city during a week was 35° C, 36°C, 34°C, 38°C, 40°C, 39°C and 44°C. What was the average daily temperature

Zigmanuir [339]

Answer:38°

Explanation:

8 0

3 years ago