<span>background information hope this helps</span>
Answer:
And what is your question
Explanation:
Answer:
Structures are given below.
Explanation:
- Treatment of 2-bromo-2-methylbutane with KOH in ethanol will give elimination of HBr through E2 mechanism.
- H atoms adjacent to Br will be eliminated.
- 2-bromo-2-methylbutane has two possible adjacent H atoms that can be eliminated giving mixture of products.
- Product of this elimination reaction is alkene. Here saytzeff fule is followed during elimination. So most substituted alkene will be major product.
- Structure of alkenes are given below.
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Formula for density is mass / volume.
100 ml is volume. 76.5g of cooking oil is
the mass.
Therefore
76.5/100 = .765g/ml