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cestrela7 [59]
3 years ago
12

Which of the following air conditions would be LEAST likely to have precipitation 10 pts

Physics
1 answer:
spayn [35]3 years ago
5 0

I see your a fan of jacksepticeye so I will help. The following answer D is correct do to the fact cold air would less likely evaporate water and two the fact that it is already dry also proves my point.


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A4 kg bowling ball begins rolling down a at bowling alloy at 6 m/s . When it strikes the pins, it is estimated to be moving at 5
Paul [167]

Answer:

Energy lost due to friction is 22 J      

Explanation:

Mass of the ball m = 4 kg

Initially velocity of ball v = 6 m/sec

So kinetic energy of the ball KE=\frac{1}{2}mv^2

KE=\frac{1}{2}\times 4\times 6^2=72J

Now due to friction velocity decreases to 5 m/sec

Kinetic energy become

KE=\frac{1}{2}\times 4\times 5^2=50J

Therefore energy lost due to friction = 72 -50 = 22 J

8 0
3 years ago
Does groundwater flow or stay still?
zhenek [66]

Answer:

yes it flows through flow paths.

Explanation:

5 0
3 years ago
How much work is needed to lift a 3kg create a vertical displacement of 22m
Ulleksa [173]
I think its W= 647.239J
6 0
3 years ago
Give at least one fact about subatomic particles
victus00 [196]

Answer:

- Particles smaller than atoms are called subatomic particles .

- There are three famous subatomic particles, proton, neutron and electron .

- The study of sub atomic particles are called particle physics

- These particles can be divided as Brayons and Leptons

- These particles are often held together by one of the four fundamental particles ( Weak force, strong force, electromagnetic force, gravitational force).

6 0
3 years ago
A 53.0-kg skater is traveling due east at a speed of 2.90 m/s. A 72.0-kg skater is moving due south at a speed of 6.20 m/s. They
soldier1979 [14.2K]

Answer:

a.\thta=71^{\circ}

b.v_f=3.78 m/s

Explanation:

We are given that

m_1=53 kg

v_1=2.9 m/s

m_2= 72 kg

v_2=6.2 m/s

a.We have to find the angle

\theta=tan^{-1}{\frac{m_2v_2}{m_1v_1}=\frac{72(6.2)}{53(2.9)}=71^{\circ}

\theta=71^{\circ}

b. We have to find the speed v_f

According to law of conservation of momentum

m_1v_1=(m_1+m_2)v_fcos\theta

53(2.9)=(53+72)v_fcos 71^{\circ}=40.7 v_f

v_f=\frac{153.7}{40.7}=3.78 m/s

3 0
3 years ago
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