m = mass of the person = 82 kg
g = acceleration due to gravity acting on the person = 9.8 m/s²
F = normal force by the surface on the person
f = kinetic frictional force acting on the person by the surface
μ = Coefficient of kinetic friction = 0.45
The normal force by the surface in upward direction balances the weight of the person in down direction , hence
F = mg eq-1
kinetic frictional force on the person acting is given as
f = μ F
using eq-1
f = μ mg
inserting the values
f = (0.45) (82) (9.8)
f = 361.6 N
Answer: Your answer is 1250J
Explanation:
K
E
=
1/2
m
v
2
The mass is
m
=
25
k
g
The velocity is v
=
10
m
s
−
1
So,
K
E
=
1
/2
x25
x
10
2^2=
1250
J
pls mark brainiest answer
Answer:
Liquid
Explanation:
Substance that assumes shape of the container, slides past each other, has no definite shape but definite volume, not easily compressible, and flows easily.
Answer:
1 m
Explanation:
Given
The mirror is a concave mirror.
Radius of curvature = 2 m
Now, for a parallel beam after reflection occurs, the object should be placed at the focus of the mirror.
We know, focal length = radius of curvature / 2
= 2 / 2
= 1
Thus the focal length is 1 m.
Hence the object should be placed at 1 m from the concave mirror for parallel beam reflection.
Answer:
S=
2
1
gt
2
........(1)
And that of the other stone is
S=u(t−n)+
2
1
[g(t−n)
2
]........(2)
Since both the stones meet at the distance so equation (1)and equation(2) will be equal
2
1
gt
2
=u(t−n)+
2
1
[g(t−n)
2
]
gt
2
=2ut−2un+gt
2
+gn
2
−2gnt
t(2gn−2u)=gn
2
−2un
t=
(gn−u)
n(
2
gn
−u)
now putting value of t in equation(1)
s=
2
g
⎣
⎢
⎡
gn−u
2
[n(
2
gn
−u)]
⎦
⎥
⎤
2
S=
2
g
⎣
⎢
⎡
(gn−u)
2
n(
2
gn
−u)
⎦
⎥
⎤
Explanation:
plzzz mark me brainliest and follow me
l
i will also follow u
