Answer is: hydrogen (cathode), iodine (anode).
The balanced
oxidation half reaction: 2I⁻(aq) →
I₂(s) + 2e⁻.<span>
Iodine is oxidized (lost electrons) from -1
to neutral charge (0).
The balanced reduction
half-reaction: 2H</span>₂O(l) + 2e⁻ → H₂(g) + 2OH⁻.<span>
<span>Hydrogen is reduced (gain electrons) from
+1 to neutral charge.</span></span>
When any atom loses two charged particles, it becomes an ion, with a charge opposite of the particles it lost. Ions will attempt to join up with other ions in ionic bonds, held together by the opposite charges of the atoms.
Answer:
What is the frequency of a 6.9 x 10-13 m wave? 3.00 x 108 = 6.9x10-13 mly). GAMMA. V = 4.35 x 10 20 5-11. 3. What is the wavelength of a 2.99 Hz wave?
Missing: 3.98 77 
Explanation:
As with most stoichiometry problems, it is necessary to work in moles. The ratio of the moles of each element will provide the ratio of the atoms of each element.
Get the mass of each element by assuming a certain overall mass for the sample (100 g is a good mass to assume when working with percentages).
Remeber that percentages are a ratio multiplied by 100. You must convert percentages back to their decimal value before working with them.
(.4838) (100 g) = 48.38 g C
(.0812 ) (100 g) = 8.12 g H
(.5350) (100 g) = 53.38 g O
Convert the mass of each element to moles of each element using the atomic masses.
(48.38 g C) (1 mol/ 12.10 g C) = 4.028 mol C
(8.12 g H) (1 mol/ 1.008 g H) = 8.056 mol H
(53.38 g O) (1 mol/ 16.00 g O) = 3.336 mol O
Find the ratio or the moles of each element by dividing the number of moles of each by the smallest number of moles.
Use the mole ratio to write the empirical formula.
