Answer:
THE LENGTH OF THE AIR COLUMN IS 9.5 CM
Explanation:
Taking the atmospheric pressure to be 760 mmHg;
When the capillary tube is held horizontally, the pressure of the tube is 760 mmHg
when the capillary tube is held vertically, the pressure increases by 4 cm = 40 mm
The new pressure of the tube is hence, 760 + 40 mmHg = 800 mmHg
Using the pressure forlmula;
P1 V1 = P2 V2
P1 A1 L1 = P2 A2 L2
where A1 and A2 is the area of the capillary tube and it is equal, it cancels out.
P1 l1 = P2 l2
l2 = P1 l1 / P2
l2 = 760 * 10 / 800
l2 = 9.5 cm
The length of the air in the tube is 9.5 cm.
Answer:
option D is correct
Explanation:
no of moles in 3 grams of HCL=3/36=0.08
if 1 mole of HCL require 1 mole of NaOH then 0.08 moles required 0.08 moles of NaOH
mass of 0.08 moles of NaOH=moles*molar mass=0.08*40=3.2 grams
so 3 grams are required in the reaction
Answer:
Kc = 6x10⁻⁶
Explanation:
For the reaction:
4NH₃(g) + 3O₂(g) ⇄ 2N₂(g) + 6H₂O(g)
Kc is defined as:
Kc =[N₂]² [H₂O]⁶ / [NH₃]⁴ [O₂]³
The equilibrium concentrations of the gases is -Because volume of the container is 1.00L-:
[N₂] = 2X = 1.96x10⁻³; <em>X = 9.8x10⁻⁴</em>
[H₂O] = 6X; 6ₓ9.8x10⁻⁴ = 5.88x10⁻³
[NH₃] = 0.0150M - 4X = 0.01108M
[O₂] = 0.0150M - 3X = 0.01206M
Replacing in Kc expression:
Kc =[1.96x10⁻³]² [5.88x10⁻³]⁶ / [0.01108M]⁴ [0.01206M]³
<h3>Kc = 6x10⁻⁶</h3>
