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3 years ago

What is the formula for the compound dinitrogen pentoxide? n4o5 n5o4 n4o6 n5o2 n2o5?

Chemistry

2 answers:

Snezhnost [94]3 years ago

6 0

Answer: $N_2O_5$

Explanation:

Dinitrogen pentoxide is a covalent compound because sharing of electrons takes place between nitrogen and oxygen. Both the elements are non-metals and hence, will form covalent bond.

The nomenclature of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written then, and a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Thus the chemical formula for dinitrogen pentoxide is $N_2O_5$

STALIN [3.7K]3 years ago

5 0

N2, penta means 5, so 5 oxygens

so with that being said n205

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Answer:

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Explanation:

In balancing a chemical equation we make sure the number of atoms of each element on the reactant side of the equation equals that on the product side

$NH_{4}Cl + Ba(NO_{3} )_{2}$ ⇒ $BaCl_{2} + NH_{4}NO_{3}$

The equation above represents an unbalanced equation of the reaction of aqueous ammonium chloride with aqueous barium nitrate .we can balance this equation by adding the right coefficients to reactants and product.

$2NH_{4}Cl + Ba(NO_{3} )_{2}$ ⇒ $BaCl_{2} + 2NH_{4}NO_{3}$

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3 years ago

How many grams of magnesium acetate are in 8.95x10^23 formula units?

Natasha_Volkova [10]

Answer:

211.63 g.

Explanation:

Particles could refer to atoms, molecules, formula units.

Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).

Using cross multiplication:

1.0 mole → 6.022 x 10²³ molecules.

??? mole → 8.95 x 10²³ molecules.

The no. of moles of magnesium acetate = (8.95 x 10²³ molecules) (1.0 mole) / (6.022 x 10²³ molecules) = 1.486 mol.

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cricket20 [7]

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3 years ago

Calculate the adjusted retention times for both pentafluorobenzene and benzene if the elution time for unretained solute is 1.06

vovangra [49]

Answer:

Pentafluorobenzene: 11,92 min

Benzene: 12,14 min

Explanation:

Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.

The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:

tr' = tr - 1,06min

For pentafluorobenzene:

tr' = 12,98min - 1,06min = 11,92 min

For benzene:

tr' = 13,20 - 1,06min = 12,14 min

I hope it helps!

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3 years ago