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erica [24]
3 years ago
12

Calculate the adjusted retention times for both pentafluorobenzene and benzene if the elution time for unretained solute is 1.06

minute.
a) 12.98 min for pentafluorobenzene and 11.92 min for benzene
b) 13.20 min for pentafluorobenzene and 12.14 min for benzene
Chemistry
1 answer:
vovangra [49]3 years ago
3 0

Answer:

Pentafluorobenzene: 11,92 min

Benzene: 12,14 min

Explanation:

<em>Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.</em>

The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:

tr' = tr - 1,06min

For pentafluorobenzene:

tr' = 12,98min - 1,06min = <em>11,92 min</em>

For benzene:

tr' = 13,20 - 1,06min = <em>12,14 min</em>

<em></em>

I hope it helps!

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How many bromine atoms are present in 37.9 g of CH2Br2?
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The answer to your question is: 6.55 x 10 ²³ atoms of Br

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If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?
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The pH of the monoprotic weak acid is 2.79.

<h3>What are weak acids?</h3>

The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.

The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).

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