In which part of a chemical reaction do bonds break in which part do they form?

1 answer:

3 0

Chemical bonds are broken down in the reactants while a reaction is occurring. Products are the new chemical bonds that are formed.

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Q: A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to re

blondinia [14]

M ( HCl ) = ?

V ( HCl ) = 25.5 mL in liters : 25.5 / 1000 => 0.0255 L

M ( NaOH ) = 0.113 M

V ( NaOH ) = 51.2 mL / 1000 => 0.0512 L

number of moles NaOH:

n = M x V

n = 0.113 x 0.0512 => 0.0057856 moles of NaOH

mole ratio:

HCl + NaOH = NaCl + H2O

1 mole HCl -------------- 1 mole NaOH
( moles HCl ) ----------- 0.0057856 moles NaOH

(moles HCl ) = 0.0057856 x 1 / 1

= 0.0057856 moles of HCl

M ( HCl ) = n / V

M = 0.0057856 / 0.0255

= 0.227 M

Answer A

hope this helps!

4 0

2 years ago

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If you dilute 19.0 mL of the stock solution to a final volume of 0.310 L , what will be the concentration of the diluted solutio

Dahasolnce [82]

Answer:

$M_2=0.613M_1$

Explanation:

$M_1$ = Concentration of stock solution

$M_2$ = Concentration of solution

$V_1$ = Volume of stock solution = 19 mL

$V_2$ = Volume of solution = 0.31 L= 310 mL

We have the relation

$M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{M_119}{310}\\\Rightarrow M_2=M_1\times\dfrac{19}{310}\\\Rightarrow M_2=0.613M_1$