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mario62 [17]
3 years ago
12

For each of the situations described below, the object considered is undergoing some changes. Among the possible changes you sho

uld consider are:
(Q) The object is absorbing or giving off heat.
(T) The object's temperature is changing.
(E) The object's thermal energy is changing.
(W) The object is doing mechanical work or having work done on it.
(C) The objects chemical energy is changing.

For each of the two situations, identify which of the five changes is taking place, indicating the applicable letters Q T U W C (or none) as appropriate while providing your reasoning.

a. An ice cube sits in the open air and is melting.
b. A cylinder with a piston on top contains a compressed gas and is sitting on a thermal reservoir (a large iron block that can provide or take thermal energy as the system needs). After everything has come to thermal equilibrium, the piston is moved upward somewhat (very slowly). The object to be considered is the gas in the cylinder.
Physics
1 answer:
velikii [3]3 years ago
8 0

Answer: a. (Q), (T), (E)

              b. (Q), (T), (E), (W)

Explanation: <u>Thermal</u> <u>Energy</u> and Temperature are closely related: when the temperature rises causing atoms or molecules to move, thermal energy is produced. Thermal energy is the energy within the system.

<u>Mechanical</u> <u>Work</u> is the amount of energy transferred due to an applied force.

<u>Chemical</u> <u>Energy</u> is the energy contained in the bonds of chemical structures of the molecules released when a chemical reaction happens.

Given the explanations, let's analyse the situations:

a. For an ice cube to be melting, it has to be absorbing heat, which means its thermal energy is changing and, consequently, so does its temperature;

b. First, the gas inside the cylinder reaches a thermal equilibrium, which means its thermal energy and temperature changed. Since there were  exchange of heat to reach the equilibrium, the gas absorbed or gave off heat. After the equilibrium, when the piston starts to be moved, the energy of the pressure is transferred to the gas, so mechanical work had been done.

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astra-53 [7]

Answer:

D. provide the most compelling evidence of cause-and-effect relationships.

Explanation:

3 0
3 years ago
An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc
Yanka [14]

Answer:

LED bulb = 0.145 A

Incandescent bulb = 0.909 A

CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

P=VI

Express this in terms of 'I'. This gives,

I=\frac{P}{V}

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, P_1=16\ W, V=110\ V

So, current drawn is given as:

I_1=\frac{16\ W}{110\ V}=0.145\ A

For incandescent bulb, P_2=100\ W, V=110\ V

So, current drawn is given as:

I_2=\frac{100\ W}{110\ V}=0.909\ A

For CFL bulb, P_3=24\ W, V=110\ V

So, current drawn is given as:

I_3=\frac{24\ W}{110\ V}=0.218\ A

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0
3 years ago
A small 0.14 kg metal ball is tied to a very light (essentially massless) string that is 0.9 m long. The string is attached to t
Vsevolod [243]

Answer:

a) v=2.743m/s

b) a_c = 8.363m/s^2

c) T=2.543N

Explanation:

First, calculate the height of the ball at the starting point:

y' = 0.9cos(55)

y' = 0.516

At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:

E_p=E_k\\mgh=\frac{mv^2}{2}

Solving for v:

v=\sqrt{2gh}

if h is the height loss: (l-y')

v=2.743m/s

The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):

a_c=\frac{v^2}{r}

a_c = 8.363m/s^2

To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration:

\sum{F_y}=ma_c=T-W\\T=ma_c+W\\T=m(a_c+g)\\T=0.14(8.363+9.8)\\T=2.543N

4 0
3 years ago
What does it mean when the mark on the ramrod disappears into the barrel of the muzzleloader?
bagirrra123 [75]

The firearm is unloaded.


The ramrod establishes whether the firearm is loaded or unloaded. It thrusts the bullet down the barrel. It is marked by wrapping some tape around it ( at the muzzle end ). This is to effectively signal if the muzzleloader is empty or loaded.


8 0
3 years ago
What is non-point source pollution and why is this kind of pollution hard to monitor and control?
avanturin [10]

Answer:

When the source of pollution is widely distributive in nature, it is called as the Non-point source pollution, for example, <em>acid rain</em>.

Explanation:

the source of pollution when is <em>not concentrated over a particular area</em> or any particular defined pinpoint is termed to be as the Non - point source pollution.

this type of pollution is very hard to be monitored or controlled due to its nature of widely distributive nature of the origin. It has <em>several pathways</em> for the effect to undertake and thus the control over the effect is <em>not easily accessible. </em>

For example, during rain, the tree fall off can enter water stream from any source, either be it open lake or ponds or even street fall offs.

7 0
3 years ago
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