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4 years ago

What else is produced during the replacement reaction of silver nitrate and potassium sulfate?

Chemistry

2 answers:

Hatshy [7]4 years ago

5 0

Answer: I think this is it. I really havnt done science/Chemistry in a while.

2KNO3

Explanation:

Digiron [165]4 years ago

5 0

Answer:2KNO3

Explanation: Please see attachment for explanation

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How many magnesium atoms are contained in 3.75 moles of magnesium?

Katarina [22]

In 1 mole of magnesium there are Avogadro's number of atoms are present.
Avogadro's number = 6.023 x 10²³
1 mole = 6.023 x 10²³ atoms
3.75 moles = 3.75 x 6.023 x 10²³
=2.26 x 10²⁴
So, in 3.75 moles of magnesium there are 2.26 x 10²⁴ atoms of magnesium are present.

7 0

4 years ago

Determine what’s wrong with these electronic configurations

Anika [276]

Answer:

Explanation:

19) it is 3d10 instead of 4d10

20) it is missing 3p6, and 4s2 before 3d5

21) Ra is not a noble gas

22) Cs is not a noble gas

7 0

2 years ago

A chemistry student adds a quantity of an unknown solid compound X to 5.00 L of distilled water at 15.° C . After 10 minutes of

Yuliya22 [10]

Answer:

34 g/100 mL

Explanation:

The solubility of a compound can be expressed in g/100mL, for this we must divide the mass of the compound that dissolves in the solute by the volume of the solvent.

The solvent, in this case, is water, and that mass of the solute X that dissolved is the mass that was recovered after the solvent was drained and evaporated. So the solubility of X (S) is:

S = 0.17 kg/5L

S = 170g/5000mL

S = 170g/(5*1000)mL

S = 34 g/100 mL

8 0

3 years ago

Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac

valentinak56 [21]

Answer : The value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

First we have to calculate the $\Delta G_^o$ .

Formula used :

$\Delta G^o=-RT\times \ln K_p$

Now put all the given values in this formula, we get:

$\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})$

$\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole$

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}$

$Q=8.1\times 10^{5}$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})$

$\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole$

Therefore, the value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

3 0

3 years ago

Under what conditions of temperature and pressure is a gas least soluble in water

snow_tiger [21]

The conditions of temperature and pressure in which a gas least soluble in water is low pressure and high temperature.

<h3>What is Henry Law?</h3>

The amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid, according to Henry's law.

From this law it is clear that:

As the pressure of the gas increases solubility of the gas on the liquid also increases.

But if the temperature of the liquid decreases then the solubility of the gas also increases.

Hence at low pressure and high temperature, gas is least soluble.

To know more about solubility of gas, visit the below link:

brainly.com/question/14747303

#SPJ4

7 0

2 years ago