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jasenka [17]
3 years ago
12

Convert 0.85 x 10-12 km to nm.

Chemistry
2 answers:
vitfil [10]3 years ago
8 0

Answer:

8,5 E10 nm

Explanation:

⇒ 0.85 E-2 Km * ( 1000 m / Km ) * ( 1 E9 nm / m ) = 8.5 E10 nm

⇒ 0.85 E-2 Km = 8.5 E10 nm

brilliants [131]3 years ago
7 0

Answer : The 0.85\times 10^{-12}km is equal to 0.85 nm.

Explanation :

The conversion used from kilometer (km) to nanometer (nm) is:

1km=10^{12}nm

As we are given that the distance 0.85\times 10^{-12}km. Now we have to calculate the distance in 'nm'.

As, 1km=10^{12}nm

So, 0.85\times 10^{-12}km=\frac{0.85\times 10^{-12}km}{1km}\times 10^{12}nm=0.85nm

Therefore, the 0.85\times 10^{-12}km is equal to 0.85 nm.

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Bond length is the distance between the centers of two bonded atoms. On the potential energy curve, the bond length is the inter
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Answer:

The answer is "152 pm".

Explanation:

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3 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
guajiro [1.7K]

Answer:

Kp = 0.049

Explanation:

The equilibrium in question is;

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The initial pressures are given, so lets set up the ICE table for the equilibrium:

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I              3.3        0.79           0

C              -2x           -x          2x

E             3.3 - 2x    0.79 - x    2x

We are told 2x = partial pressure of SO₃ is 0.47 atm at equilibrium, so we can determine the partial pressures of  SO₂ and O₂ as follows:

p SO₂  = 3.3 -0.47 atm = 2.83 atm

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Now we can calculate Kp:

Kp = 0.47² /[ ( 2.83 )² x 0.56 ] = 0.049 ( rounded to 2 significant figures )

Note that we have extra data in this problem we did not need since once we setup the ICE table for the equilibrium we realize we have all the information needed to solve the question.

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