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jasenka [17]
3 years ago
12

Convert 0.85 x 10-12 km to nm.

Chemistry
2 answers:
vitfil [10]3 years ago
8 0

Answer:

8,5 E10 nm

Explanation:

⇒ 0.85 E-2 Km * ( 1000 m / Km ) * ( 1 E9 nm / m ) = 8.5 E10 nm

⇒ 0.85 E-2 Km = 8.5 E10 nm

brilliants [131]3 years ago
7 0

Answer : The 0.85\times 10^{-12}km is equal to 0.85 nm.

Explanation :

The conversion used from kilometer (km) to nanometer (nm) is:

1km=10^{12}nm

As we are given that the distance 0.85\times 10^{-12}km. Now we have to calculate the distance in 'nm'.

As, 1km=10^{12}nm

So, 0.85\times 10^{-12}km=\frac{0.85\times 10^{-12}km}{1km}\times 10^{12}nm=0.85nm

Therefore, the 0.85\times 10^{-12}km is equal to 0.85 nm.

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<h3>Explanation</h3>

What's the definition of Bronsted-Lowry acids and bases?

  • Bronsted-Lowry Acid: a species that can donate one or more protons \text{H}^{+} in a reaction.
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Ammonium ions {\text{NH}_4}^{+} are positive. Protons \text{H}^{+} are also positive.

Positive charges repel each other, which means that it will be difficult for {\text{NH}_4}^{+} to accept any additional protons. As a result, it's unlikely that {\text{NH}_4}^{+} will accept <em>any</em> proton and act like a Bronsted-Lowry Base.

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Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

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