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umka2103 [35]
3 years ago
11

Data: Atom Element Protons Neutrons Electrons Net Charge Mass Number 1 2 3 4

Physics
1 answer:
m_a_m_a [10]3 years ago
5 0
Hard to hard I need help
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We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

F_D = c_D A \frac{\rho V^2}{2}

Where,

F_D = Drag Force

c_D = Drag coefficient

A = Area

\rho= Density

V = Velocity

Our values are given by,

c_D = 0.5 (That is proper of a cone-shape)

A = 9m^2

\rho = 1.2Kg/m^3

V = 6.5m/s

Part A ) Replacing our values,

F_D = 0.5*9*\frac{1.2*6.5^2}{2}

F_D = 114.075N

Part B ) To find the torque we apply the equation as follow,

\tau = F*d

\tau = (114.075N)(7)

\tau = 798.525N.m

3 0
3 years ago
In a closed system, a cart with a mass of 1.5 kg is rolling to the right at 1.4 m/s, while another cart of mass 1.0 kg is rollin
bija089 [108]

Answer: The correct option is (c.).

Explanation:

Mass of the cart A= 1.5 kg

Velocity of Cart A = 1.4 m/s towards right

Mass of the cart B = 1.0 kg

Velocity of Cart B = 1.4 m/s towards left

Momentum (P)= Mass × Velocity

P_A=1.5 kg\times 1.4 m/s=2.1 kg m/s

P_B=1.0 kg\times (-1.4m/s)=-1.4 kg m/s

(Negative sign means velocity of the cart is in opposite direction of that of the cart A)

Total Momentum =P_A+P_B=2.10 kg m/s-1.40 kg m/s=0.70 kg m/s

Hence, the correct option is (c.).

7 0
3 years ago
Read 2 more answers
suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be
ehidna [41]
Use the Inverse square law, Intensity (I)<span> of a light </span>is inversely proportional to the square of the distance(d).

I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2*D2)/(D1*D1)

L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 <span>candela</span>
3 0
3 years ago
the distance between two successive troughs of wave is 0.4m. If the frequency of the source is 825Hz, calculate the speed of the
neonofarm [45]

Answer:

speed=330m/s

Explanation:

the speed of wave is given as

speed(meter per second) =frequency(hertz) * wavelength(meters)

so using the above formula we substitute the figures given in the question in the formula we get

speed = 0.4*825

speed =330m/s

note m/s is the si unit for speed which is read as meter per second

therefore speed =330m/s

7 0
3 years ago
A 73-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m,
Gnesinka [82]

To solve this problem it is necessary to apply the concepts related to the Conservation of Energy, for which it is necessary that any decrease made through the potential energy, is equivalent to the gain given in the kinetic energy or vice versa.

Mathematically this can be expressed as

KE_i+PE_i = KE_f+PE_f

Since there is no final potential energy (the height is zero), and the initial potential energy is equivalent to the work done we have to

W = KE_f-KE_i-PE_i

W = \frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2 -mgh

W =\frac{1}{2} m(v_f^2-v_i^2)-mgh

W= \frac{1}{2}(73)(8.5^2-1.6^2)-(73*9.8*1.6)

W= 1399.045J

W= 1.4kJ

Therefore the non-conservative work was done on the boy is 1.4kJ

4 0
3 years ago
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