Answer:
vDP = 21.7454 m/s
θ = 200.3693°
Explanation:
Given
vDE = 7.5 m/s
vPE = 20.2 m/s
Required: vDP
Assume that
vDE to be in direction of - j
vPE to be in direction of i
According to relative motion concept the velocity vDP is given by
vDP = vDE - vPE (I)
Substitute in (I) to get that
vDP = - 7.5 j - 20.2 i
The magnitude of vDP is given by
vDP = √((- 7.5)²+(- 20.2)²) m/s = 21.7454 m/s
θ = Arctan (- 7.5/- 20.2) = 20.3693°
θ is in 3rd quadrant so add 180°
θ = 20.3693° + 180° = 200.3693°
Acceleration due to gravity.
Answer:
The smallest diameter is 
Explanation:
From the question we are told that
The resolution of the telescope is 
The wavelength is 
From the question we are told that

So 
Therefore


Now 
So 
=> 

The smallest diameter is mathematically represented as

substituting values


The work done by the three students is 3,000 J.
The energy transferred in the process is 3,000 J.
<h3>What is work done?</h3>
- Work done is the product of force and distance moved by the object.
W = Fd
The work done by the three students is calculated as follows;
W = 300 x 10
W = 3,000 J
<h3>What is energy transfer?</h3>
- This is means by which energy is converted from one form to another.
The energy transferred in the process is determined by work energy theorem.
E = W
E = 3,000 J
Learn more about work-energy theorem here: brainly.com/question/22236101