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umka2103 [35]
3 years ago
11

Data: Atom Element Protons Neutrons Electrons Net Charge Mass Number 1 2 3 4

Physics
1 answer:
m_a_m_a [10]3 years ago
5 0
Hard to hard I need help
You might be interested in
A copper block with a mass of 300 grams is cooled to 77 K by being immersed in liquid nitrogen. The block is then placed in a St
abruzzese [7]

Answer:

Explanation:

mass of copper m = 0.3 kg

Initial temperature t₁ 77K = 77 - 273 = -196°C

Final temperature t₂ = - 20°C

Mass of water M = ?

Initial temperature of water = 50°C

Final temperature = - 20°C

Heat lost by copper

0.3 x 385 x ( -20+ 196 )

= 20328 J

Heat lost by water to cool to 0°C

= M x4186 x (50-0)

= 209300 M

Heat lost by water to cool to freeze at 0°C

= M x 335 x 10³ J

Heat lost by ice  to cool to - 20°C

= Mx 2060 x 20

= 41200 M

Total heat gained

= 585500 M

Heat lost by water = heat gained by copper block

585500 M  =  20328

M = .03472 Kg

= 34.72 g

6 0
3 years ago
The net external force on the propeller of a 0.75 kg model airplane is 17N forward. What is the
V125BC [204]

Answer:

23 m/s

Explanation:

The net external force on the propeller is 17N

The airplane is 0.75 kg

Therefore the acceleration of the plane can be calculated as follows

= 17/0.75

= 23 m/s

Hence the acceleration of the airplane is 23 m/s

8 0
3 years ago
Newton's Laws question, please help me:
zaharov [31]
I believe that would be the second law of motion
6 0
3 years ago
A steel wire of length 4.7 m and cross section 3 x 103 m2 stretches by the same amount as a copper wire of length 3.5 m and cros
EleoNora [17]

Answer:

The ratio of the young's modulus of steel and copper is 1.79\times10^{-2}

(c) is correct option.

Explanation:

Given that,

Length of steel wire = 4.7 m

Cross sectionA = 3\times10^{-3}\ m^2

Length of copper wire = 3.5 m

Cross sectionA = 4\times10^{-5}\ m^2

We need to calculate the ratio of young's modulus of steel and copper

Using formula of young's modulus for steel wire

Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta l}{l}}

Y_{s}=\dfrac{Fl_{s}}{A_{s}\Delta l}....(I)

The young's modulus for copper wire

Y_{c}=\dfrac{Fl_{c}}{A_{c}\Delta l}....(II)

From equation (I) and (II)

The ratio of the young's modulus of steel and copper

\dfrac{Y_{s}}{Y_{c}}=\dfrac{\dfrac{Fl_{s}}{A_{s}\Delta l}}{\dfrac{Fl_{c}}{A_{c}\Delta l}}

\dfrac{Y_{s}}{Y_{c}}=\dfrac{A_{c}\times l_{s}}{A_{s}\times l_{c}}

\dfrac{Y_{s}}{Y_{c}}=\dfrac{4\times10^{-5}\times4.7}{3\times10^{-3}\times3.5}

\dfrac{Y_{s}}{Y_{c}}=1.79\times10^{-2}

Hence, The ratio of the young's modulus of steel and copper is 1.79\times10^{-2}

5 0
3 years ago
What is Ohm's Law, and how does it work in real life.
Firdavs [7]

Explanation:

Ohms law states that the electrical current present in a metallic conductor is directly proportional to the potential difference between the metallic conductor and inversely proportional to the resistance therefore if the voltage is increased resistance also increases provided that temperature and other physical properties remains constant V=IR

8 0
3 years ago
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