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Dmitry_Shevchenko [17]
3 years ago
14

What is the medium of ocean waves? I put extra points so

Physics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
The medium of ocean waves are In the case of a water wave in the ocean, the medium through which the wave travels is the ocean water. In the case of a sound wave moving from the church choir to the pews, the medium through which the sound wave<span> travels is the air in the room.</span>
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Given that a lever has a mechanical advantage of 6.0 and is 100% efficient, if the resistance is to be lifted 2.0 inches, then h
Shalnov [3]
The mechanical advantage of a machine is the ratio of the force produced by the machine to the force applied to it. Therefore, we may calculate the applied force using:
Mechanical advantage = force by machine / force applied
6 = 2 / force applied
Force applied = 1/3

Thus, the distance that the effort must move will be 1/3 inch
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4 years ago
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9- Un auto <br> Recorre 500m en 4 segundos, calcula la velocidad promedio.
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Answer:

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Explanation:

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3 years ago
An electron moves through a uniform electric field E = (2.00î + 5.40ĵ) V/m and a uniform magnetic field B = 0.400k T. Determine
EleoNora [17]

Answer:a=1.75\times 10^{21}\left ( 2\hat{i}5.08\hat{j}\right )

Explanation:

Given

Electric Field \vec{E}=2\hat{i}+5.4\hat{j}

\vec{B}=0.4\hat{k}\ T

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Force on a charge Particle moving in Magnetic Field

F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]

a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}

a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}  

a=1.75\times 10^{21}\left ( 2\hat{i}+5.08\hat{j}\right )\ m/s^2

7 0
3 years ago
An isolated conducting sphere has a 12 cm radius. One wire carries a current of 1.0000049 A into it while another wire carries a
tatuchka [14]

Answer:

it will take for the sphere to increase in potential by 1500 V, 503.71 s.

Explanation:

The charge on the sphere after t seconds is:

q = (1.0000049 - 1.0000000) t = 0.0000049 t

The voltage on the surface is

V = k * \frac{q}{R} = k 0.0000049 t / R

solve for t

t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 * 9e^{9}) = 503.71 s

7 0
4 years ago
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It is a turn off engine
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