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ki77a [65]
4 years ago
8

A circuit contains three resistors connected in series. the value of r1 is 150 , the value of r2 is 60 , and the value of r3 is

620 . what is the total resistance in the circuit?
Computers and Technology
2 answers:
vlada-n [284]4 years ago
7 0
For calculating the total value of the resistances in a series circuit, we just add all of the values. In this case, it would be 150+60+620 which is 830Ω
tresset_1 [31]4 years ago
5 0

Answer:

830 Ω

Explanation:

For the resistors connected in series the voltage flowing through them is different while the current flowing through them is the same.

The reason for the different voltages flowing through each resistor in series is due to the resistance that each resistor preceding the other poses to the voltage that is passed through it. the formula used for calculating resistance of resistors in series is = R1 + R2 + R3 while for calculating resistance in parallel is = 1/R1 + 1/R2 + 1/R3 = 1/Ret

R1 + R2 + R3 = 150 + 60 + 620 = 830 Ω

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6 0
3 years ago
The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app
LUCKY_DIMON [66]

Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

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// if n=0 then return 1

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{

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int n;

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Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

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