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Firdavs [7]
3 years ago
7

A radio wave has a wavelength of 300 m. The wave moves with a speed of 3.0 × 108 m/s. What is the frequency of the radio wave? A

. 1.0 × 106 Hz B. 1.0 × 10-5 Hz C. 1.0 × 10-6 Hz D. 1.0 × 105 Hz
Physics
1 answer:
NemiM [27]3 years ago
5 0

           Frequency  =  (speed)  /  (wavelength)

                             = (3 x 10⁸ m/s)  /  (300 m)

                             =      1 x 10⁶ per sec

                             =      1 mHz 

This frequency is the " 1000 " or " 100 " that's marked
in the middle of your AM radio dial.

If there's an AM station in your city that broadcasts on 1000 kHz
and you tune your radio to it, you're picking up radio waves 
that are 300 meters long.  (about 0.19 of a mile)
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Answer:

a) n2 = 1.55

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c) 4.74*10^14 Hz

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Explanation:

a) To find the index of refraction of the syrup solution you use the Snell's law:

n_1sin\theta_1=n_2sin\theta_2   (1)

n1: index of refraction of air

n2: index of syrup solution

angle1: incidence angle

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You replace the values of the parameter in (1) and calculate n2:

n_2=\frac{n_1sin\theta_1}{sin\theta_2}=\frac{(1)(sin30.2\°)}{sin18.82\°}=1.55

b) To fond the wavelength in the solution you use:

\frac{\lambda_2}{\lambda_1}=\frac{n_1}{n_2}\\\\\lambda_2=\lambda_1\frac{n_1}{n_2}=(632.8nm)\frac{1.00}{1.55}=408.25nm

c) The frequency of the wave in the solution is:

v=\lambda_2 f_2\\\\f_2=\frac{v}{\lambda_2}=\frac{c}{n_2\lambda_2}=\frac{3*10^8m/s}{(1.55)(408.25*10^{-9}m)}=4.74*10^{14}\ Hz

d) The speed in the solution is given by:

v=\frac{c}{n_2}=\frac{3*10^8m/s}{1.55}=1.93*10^8m/s

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