Answer:
37 W
Explanation:
Power is the time rate of dissipation or absorbing energy. The power supplied or absorbed by an element is the product of the current flowing through the element and the voltage across the element. Power is measured in watts. If the power is positive then it is absorbed by the element and if it is negative then it is supplied by the element.
Power = voltage * current
For element A: Power = 36 V * -4 A = -144 W
For element B: Power = -20 V * -4 A = 80 W
For element C: Power = -24 V * 4 A = -94 W
For element D: Power = -80 V * -1.5 A = 120 W
For element E: Power = 30 V * 2.5 A = 75 W
The total power developed in the circuit = sum of power through the element = (-144 W) + 80 W + (-94 W) + 120 W + 75 W = 37 W
The electrostatic force between two charged object is given by:
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the separation between the two objects
We see that the force is inversely proportional to the square of the distance:
. Therefore, if the distance is doubled, the force decreases by a factor 4, and the new force will be:
and it will still be a repulsive force, since the two balloons have charges of same sign.
Answer:
0
Explanation:
It’s before the projectile was fired, so nothing has happened yet.
Answer:
d = 369.38 km
Explanation:
The speed has a x-component and a y-component.
speed,x = 2.07cos(28.8°) = 1.81 km/s
speed,y = 2.07sin(28.8°) = 1.00 km/s
The time the shell flies is determined by the y-component, when it reaches the highest point the speed is 0 due to the gravitational acceleration.
0 = 1000 - 9.8 * t
9.8 * t = 1000
t = 102.04 s
After reaching the highest point the shell takes the same time to reach the ground where it was fired, so the total time it flies is 102.04* 2 = 204.08 s
Now you can calculate the distance it moves horizontally while it flies (constant speed)
d = 1.81 km/s * 204.08 s (I used the speed in km/s because the answer needs to be in km)
d = 369.38 km
Answer:
Final velocity, V = 11.5m/s
Explanation:
Given the following data;
Initial velocity, U = 2.5m/s
Acceleration, a = 1.5m/s²
Time, t = 6secs
To find the final velocity, we would use the first equation of motion
V = U + at
Substituting into the equation, we have
V = 2.5 + 1.5*6
V = 2.5 + 9
Final velocity, V = 11.5m/s