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3 years ago

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A radio wave has a wavelength of 300 m. The wave moves with a speed of 3.0 × 108 m/s. What is the frequency of the radio wave? A

. 1.0 × 106 Hz B. 1.0 × 10-5 Hz C. 1.0 × 10-6 Hz D. 1.0 × 105 Hz

1 answer:

NemiM [27]3 years ago

5 0

   Frequency = (speed) / (wavelength)

   = (3 x 10⁸ m/s) / (300 m)

   = 1 x 10⁶ per sec

   = 1 mHz

This frequency is the " 1000 " or " 100 " that's marked
in the middle of your AM radio dial.

If there's an AM station in your city that broadcasts on 1000 kHz
and you tune your radio to it, you're picking up radio waves
that are 300 meters long. (about 0.19 of a mile)

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The time it takes the plane to change its velocity is 9s.

<h3>What is time?</h3>

Time can be defined the measured or measurable period during which an action, process, or condition exists or continues.

To calculate the time it takes the airplane to change its velocity, we use the formula below.

Formula:

t = (v-u)/a.......... Equation 1

Where:

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From the question,

v = 40 m/s
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Substitute these values into equation 1

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2 years ago

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miss Akunina [59]

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3 years ago

Determine the speed, wavelength, and frequency of light from a helium-neon laser as it travels through polystyrene. The waveleng

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Answer:

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Wavelength:

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Frequency:

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Explanation:

The speed of the laser as it travels through polystyrene can be determine by means of the equation of the refraction index:

$n = \frac{c}{v}$ (1)

Where c is the speed of light and v is the speed of the laser in the medium.

Therefore, v will be isolated from equation 1

$v = \frac{c}{n}$

$v = \frac{3x10^{8}m/s}{1.490}$

$v = 2.01x10^{8}m/s$

Hence, the speed of the laser has a value of $2.01x10^{8}m/s$

Frenquency:

Since, wavelength is the only one who depends on the media. Therefore the frequency in both medium will be the same.

To determine the frequency it can be used the following equation

$c = \nu \cdot \lambda$ (2)

Where c is the speed of light, $\nu$ is the frequency and $\lambda$ is the wavelength

Then, $\nu$ wil be isolated from equation 2.

$\nu = \frac{c}{\lambda}$ (3)

Before using equation 3 it is necessary to express $\lamba$ in units of meters.

$\lambda = 632.8nm . \frac{1m}{1x10^{9}nm}$ ⇒ $6.328x10^{-7}m$

$\nu = \frac{3x10^{8}m/s}{6.328x10^{-7}m}$

$\nu = 4.74x10^{14}s^{-1}$

$\nu = 4.74x10^{14}Hz$

Hence, the frequency of the laser has a value of $4.74x10^{14}Hz$

Wavelength:

To determine the wavelength it can be used:

$v = \nu \cdot \lambda$

$\lambda = \frac{v}{\nu}$

Where v is the speed of the laser through the polystyrene.

$\lambda = \frac{2.01x10^{8}m/s}{4.74x10^{14}s^{-1}}$

$\lambda = 4.24x10^{-7}m$

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What is terminal velocity and how is it reached?

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He thermal velocity or thermal speed is a typical velocity of the thermal motion of particles which make up a gas, liquid, etc. Thus, indirectly, thermal velocity is a measure of temperature. Technically speaking it is a measure of the width of the peak in the Maxwell–Boltzmann particle velocity distribution.

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