For this
specific problem, the maximum value for d is 52m. I am hoping
that this answer has satisfied your query about and it will be able to help
you, and if you’d like, feel free to ask another question.
Answer
given,
x = 4 t³ - 6 t² + 12
velocity,
For minimum velocity calculation we have differentiate it and put it equal to zero.
.........(1)
putting it equal to zero
24 t - 12 =0
t = 0.5 s
At t = 0.5 s velocity will be minimum.
b) minimum velocity
v = 12t² -12 t
v = 12 x 0.5² -12 x 0.5
v = -3 m/s
c) derivative of velocity w.r.t. time is acceleration
from equation 1
a = 24 t - 12
time at which acceleration will be zero
0 = 24 t - 12
t = 0.5 s
At t = 0.5 s acceleration will be zero.
I think it would'nt move at all but im not postive
Answer:
A projectile is launched from and returns to ground level, as the figure shows. There is no air resistance. The horizontal range of the projectile is measured to be R= 167 m, and the horizontal component of the launch velocity is v0x = 22.0 m/s. Find the vertical component v0y of the projectile
Explanation:
bhai figure kaha hai