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Shkiper50 [21]
3 years ago
11

A car traveling at 35 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration.

Physics
1 answer:
Pepsi [2]3 years ago
7 0
Sorry i dontknow da answrs]
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Which statement is true about the atom?
slavikrds [6]

Answer:

Its d

atome contain

negative electrons,

positive protons and uncharged neutrons.

Explanation:

7 0
3 years ago
Two hypothetical discoveries in Part A deal with moons that, like Earth's moon, are relatively large compared to their planets.
ser-zykov [4K]

Answer:

Explanation:

Solution:

- Finding large moons comparable in size to their planets result from impacts of two astro-bodies. The probability of such an event occurring is very rare.

- Even at the best luck, one moon can be made from the result of giant impact. While the probability of 6 planets having moons of comparable sizes is close to impossible.

6 0
3 years ago
What happens when the mass of an object is greter
Paul [167]
The acceleration goes up.
4 0
3 years ago
A large uniform chain is hanging from the ceiling, supporting a block of mass 46 kg. The mass of the chain itself is 19 kg, and
docker41 [41]

Answer:

T = 451.26 N

Explanation:

It is given that,

The mass of block, m = 46 kg

Mass of the chain, m' = 19 kg

Length of the chain, l = 1.9 m

Let T is the the tension in the chain at the point where the chain is supporting the block. It is clearly equal to the product of mass and acceleration.

T=mg

T=46\ kg\times 9.81\ m/s^2

T = 451.26 N

So, the tension in the chain at the point where the chain is supporting the block is 451.26 N. Hence, this is the required solution.

4 0
3 years ago
Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph .
Serggg [28]

Answer:

t = 25.5 min

Explanation:

To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.

t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h

Next, you calculate the difference between both times t1 and t2:

\Delta t=t_1-t_2=2.30h-1.875h=0.425h

This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:

0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s

hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph

3 0
2 years ago
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