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3 years ago

What does x represent on a motion in physics

1 answer:

7 0

The variable xxx is often used to represent the horizontal position. The variable y is often used to represent the vertical The airplane passenger’s initial position is x_0=6.0\text{ m}x0=6.0 mx, start subscript, 0, end subscript, equals, 6, point, 0, space, m and his final position is x_f=2.0\text{ m}xf=2.0 mx, start subscript, f, end subscript, equals, 2, point, 0, space, m, so his displacement can be found as follows,Δx=xf−x0=2.0 m−6.0 m=−4.0 m. His displacement is negative because his motion is toward the rear of the plane, or in the negative x direction in our coordinate system.position.

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A 1.2 m long wave travels 11.2 m to a wall and back again in 4.0 s. What is

algol [13]

Answer:

f = 4.67 Hz

Explanation:

We can approximate the wave as a traveling wave, therefore the speed of the wave is constant

v = d / t

the total distance remember, in going to the wall and back is

d = 2 11.2 = 22.4 me

we substitute

v = 22.4 / 4.0

v = 5.6 m / s

now we can use the relationship between the speed of the wave, its wavelength and u frequency

v =λ f

f = v /λ

f = 5.6 / 1.2

f = 4.67 Hz

3 0

3 years ago

A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia

Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0

3 years ago

A dolphin jumps out of the water. As it falls back down it a clerated at a rate of -9,8m/s^2 for 0.8 seconds of free fall. To ca

Anettt [7]

Answer:

0.196 m

Explanation:

Given in the question that,

time taken by the dolphin to go back to water = 0.2 sec

To solve the question we will use Newton's Law of motion

here S is distance covered

u is initial speed

a = acceleration due to gravity

t = time taken

Plug value in the equation above

S = 0(0.2) + 0.5(-9.8)(0.2)²

S = 0.5(-9.8)(0.2)²

S = -0.196 m

Negative sign represent direction

(Assuming that dolphin have a vertical straight jump not a projectile motion)

4 0

3 years ago

A voltage amplifier needs a high input resistance and a low output resistance. Select one: True False

cupoosta [38]

Answer:

Explanation:

In electric circuit , the potential difference is always developed across the resistance .

Now is we are to amplify the voltage , that means low input voltage is converted into high voltage output .

Therefore we require low resistance at input for low voltage and high out put resistance for high output

Thus the statement given is wrong .

6 0

3 years ago

A circular loop of wire 75 mm in radius carries a current of 113 A. Find the (a) magnetic field strength and (b) energy density

Roman55 [17]

The magnetic field strength is 9.47 ×10⁻⁴ T

The energy density at the center of the loop is 0.36 J/m³

<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

$B = \frac{\mu_{0} I}{2R}$

Where B is the magnetic field strength

$\mu_{0}$ is the permeability of free space $(\mu_{0}=4\pi \times 10^{-7} \ N/A^{2})$

$I$ is the current

and R is the radius

From the give information,

$R = 75 \ mm= 75 \times 10^{-3} \ m$

and $I = 113 \ A$

Putting the parameters into the formula, we get

$B = \frac{4\pi \times 10^{-7} \times 113}{2 \times 75 \times 10^{-3} }$

$B = 9.47 \times 10^{-4} \ T$

Hence, the magnetic field strength is 9.47 ×10⁻⁴ T

Now, for the energy density

Energy density can be calculated by using the formula,

$u_{B} = \frac{B^{2} }{2\mu_{0} }$

Where $u_{B}$ is the energy density

Then,

$u_{B}= \frac{(9.47\times 10^{-4} )^{2} }{2 \times 4\pi \times 10^{-7} }$

$u_{B} = 0.36 \ J/m^{3}$

Hence, the energy density at the center of the loop is 0.36 J/m³

Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557

7 0

2 years ago