The variable <span><span>xx</span>x</span><span> is often used to represent the horizontal position. The variable y</span> is often used to represent the vertical <span>The airplane passenger’s initial position is </span><span><span>x_0=6.0\text{ m}<span><span>x<span><span>0</span><span></span></span></span>=6.0<span> m</span></span></span>x, start subscript, 0, end subscript, equals, 6, point, 0, space, m</span><span> and his final position is </span><span><span>x_f=2.0\text{ m}<span><span>x<span><span>f</span><span></span></span></span>=2.0<span> m</span></span></span>x, start subscript, f, end subscript, equals, 2, point, 0, space, m</span>, so his displacement can be found as follows,<span>Δx=<span>xf</span>−<span>x0</span>=2.0 m−6.0 m=−4.0 m</span><span>. His displacement is negative because his motion is toward the rear of the plane, or in the negative x direction in our coordinate system.</span>position.
This is an interesting (read tricky!) variation of Rydberg Eqn calculation. Rydberg Eqn: 1/λ = R [1/n1^2 - 1/n2^2] Where λ is the wavelength of the light; 1282.17 nm = 1282.17×10^-9 m R is the Rydberg constant: R = 1.09737×10^7 m-1 n2 = 5 (emission) Hence 1/(1282.17 ×10^-9) = 1.09737× 10^7 [1/n1^2 – 1/25^2] Some rearranging and collecting up terms: 1 = (1282.17 ×10^-9) (1.09737× 10^7)[1/n2 -1/25] 1= 14.07[1/n^2 – 1/25] 1 =14.07/n^2 – (14.07/25) 14.07n^2 = 1 + 0.5628 n = √(14.07/1.5628) = 3
