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Dafna11 [192]
3 years ago
14

What does x represent on a motion in physics

Physics
1 answer:
lianna [129]3 years ago
7 0
The variable <span><span>xx</span>x</span><span> is often used to represent the horizontal position. The variable y</span> is often used to represent the vertical <span>The airplane passenger’s initial position is </span><span><span>x_0=6.0\text{ m}<span><span>x<span><span>​0</span><span>​​</span></span></span>=6.0<span> m</span></span></span>x, start subscript, 0, end subscript, equals, 6, point, 0, space, m</span><span> and his final position is </span><span><span>x_f=2.0\text{ m}<span><span>x<span><span>​f</span><span>​​</span></span></span>=2.0<span> m</span></span></span>x, start subscript, f, end subscript, equals, 2, point, 0, space, m</span>, so his displacement can be found as follows,<span>Δx=<span>xf</span>−<span>x0</span>=2.0 m−6.0 m=−4.0 m</span><span>. His displacement is negative because his motion is toward the rear of the plane, or in the negative x direction in our coordinate system.</span>position. 
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Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the workdone by Ryan?​
Xelga [282]
<h2><u>Question</u><u>:</u><u>-</u></h2>

Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?

<h2><u>Answer:</u><u>-</u></h2>

<h3>Given,</h3>

=> Force applied by Ryan = 10N

=> Distance covered by the book after applying force = 30 cm

<h3>And,</h3>

30 cm = 0.3 m (distance)

<h3>So,</h3>

=> Work done = Force × Distance

=> 10 × 0.3

=> 3 Joules

\small \boxed{work \: done \:  by \: Ryan \:  = 3 \: Joules}

4 0
3 years ago
"Darwin's finches" reside on the Galapagos Islands. Each species has a different type of beak, however, they can all be traced b
Ivahew [28]
It would be adaptation because the finches live in different islands and each have different weather and  resources  
3 0
3 years ago
Read 2 more answers
The speaker at the concert has the sound intensity level of 100 dB if we listen from the distance 5 m.How far from the speaker d
Mademuasel [1]

Answer:

28.11m far from the speaker the intensity drops to 85 dB.

Explanation:

In the equation for the Decibel scale

  (1). \: \:\beta =10 log(\dfrac{I}{I_0})

The ratio of the intensities can be written as

$ \frac{I}{I_0} = \dfrac{\frac{P}{A} }{\frac{P}{A_0} } $

\dfrac{I}{I_0} = \dfrac{A_0}{A}.

And since

A = 4\pi r^2

and

A_0 = 4 \pi r_0^2,

\dfrac{A_0}{A} = \dfrac{4 \pi r_0^2}{4 \pi r^2}  = \dfrac{r_0^2}{r^2}

meaning

\dfrac{I}{I_0} = \dfrac{r_0^2}{r^2}.

Putting this into equation (1), we get:

\boxed{ (2).\: \: \beta = 10log(\dfrac{r_0^2}{r^2})}

Now, if the intensity is 100 dB when the distance is 5 meters, we have:

100dB=10 log(\dfrac{r_02}{(5m)^2})

10= log(\dfrac{r_0^2}{25})

by taking both sides to the exponent:  

10^{10}= \dfrac{r_0^2}{25}

r^2 = 25 *10^{10}\\r = 5 *10^5

Now equation (2) becomes

\beta = 10log(\dfrac{25*10^{10}}{r^2})

when the intensity level is 85 dB we have

85 = 10log(\dfrac{25*10^{10}}{r^2})

8.5 = log(\dfrac{25*10^{10}}{r^2})

take both sides to exponents and we get:

10^{8.5} =10^{ log(\dfrac{25*10^{10}}{r^2})}

10^{8.5} =\dfrac{25*10^{10}}{r^2}

r^2 = \dfrac{25*10^{10}}{10^{8.5}}

\boxed{r = 28.11m}

Thus, 28.11m far from the speaker the intensity drops to 85 dB.

7 0
3 years ago
The low areas created as a sound wave propagates are called rarefactions
qwelly [4]

The answer is; pressure

The sound is a longitudinal wave meaning the particles vibrate parallel to the direction of the wave. Sound waves, therefore, produce compression (akin to the crest in a transverse wave) and rarefaction regions (akin to a trough in a transverse wave) as its energy is propagated in the medium.  


8 0
4 years ago
Read 2 more answers
Which of the following is true of greenhouse gases?
Sedaia [141]

Answer:

A. They trap energy in the atmosphere.

Explanation:

Greenhouse gases are defined as gases that absorb and emit radiation within the infrared range. These gases allow the sun’s rays to pass through the ozone layer and warm the earth, but prevent this warmth from escaping atmosphere.

Greenhouse gases cause the greenhouse effect on planets. Examples of greenhouse gases in Earth's atmosphere are water vapor, carbon dioxide, methane, ozone etc.

4 0
3 years ago
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