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3 years ago

The mass of a diamond that has a volume of 0.35cm3

Chemistry

1 answer:

MAXImum [283]3 years ago

3 0

Answer:

1.225g

Explanation:

From the question given,

Volume of diamond = 0.35cm^3

Density of diamond = 3.5g/cm^3

Mass of diamond =?

Density = Mass /volume

Mass = Density x volume

Mass = 3.5 x 0.35

Mass of diamond = 1.225g

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Carbon dating requires that the object being tested contain

luda_lava [24]

Answer:

Organic Material

Explanation:

Carbon Dating is the process in which the age of a piece of organic matter is determined by the proportions of carbon isotopes it contains.

4 0

3 years ago

What is the volume occupied by 2.34 grams of CO2 gas at STP?

krok68 [10]

Answer:

The volume occupied by 2.34 grams of CO2 gas at STP is 1.18 L

8 0

3 years ago

Place the following transitions of the hydrogen atom in order from longest to shortest wavelength of the photon emitted. Rank fr

gizmo_the_mogwai [7]

Answer:

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Explanation:

We can use the Rydberg formula which relates the wavelength of the photon emissions to the principle quantum numbers involved in the transition:

$\frac{1}{\lambda}=R((\frac{1}{n_1^2})-(\frac{1}{n_2^2}))$

with $n_1$ final n, and $n_2$ initial n

evaluating for each transition:

7 to 4 $\frac{1}{\lambda} = R((\frac{1}{4^2})-(\frac{1}{7^2}))= R(1/16-1/49)=R(0.042)$

5 to 3 $\frac{1}{\lambda}= R(1/9-1/25)=R(0.071)$

4 to 2 $\frac{1}{\lambda}= R(1/4-1/16)=R(0.1875)$

3 to 2 $\frac{1}{\lambda}= R(1/4-1/9)=R(0.139)$

Note that the above formula is written for $\frac{1}{\lambda}$ , so lower $\frac{1}{\lambda}$ value obtained involves higher $\lambda$ .

So we should order from lower to higher $\frac{1}{\lambda}$

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Note: Take into account that longer wavelength involves lower energy ( $E=\frac{hc}{\lambda}$ ).

3 0

3 years ago

An unknown gas effuses at one half the speed of oxygen. What is the molar mass of the unknown? It is either HBr or HI. Which gas

sertanlavr [38]

Answer:

HI.

Explanation:

Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.

Rate of effusion ∝ 1/√molar mass.

(Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

An unknown gas effuses at one half the speed of that of oxygen.

∵ Rate of effusion of unknown gas = 1/2 (Rate of effusion of O₂)

∴ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = 2.

Molar mass of O₂ = 32.0 g/mol.

∵ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

∴ 2.0 = (√molar mass of unknown gas) / √32.0.

( √molar mass of unknown gas) = 2.0 x √32.0

By squaring the both sides:

∴ molar mass of unknown gas = (2.0 x √32.0)² = 128 g/mol.

∴ The molar mass of sulfur dioxide = 80.91 g/mol and the molar mass of HI = 127.911 g/mol.

So, the unknown gas is HI.

5 0

3 years ago

What's the chemical formula for salt, like is it NaCl?? the salt we eat???????

MA_775_DIABLO [31]

yeah it's NaCl, I just looked it up

3 0

2 years ago

Read 2 more answers