They are all transioning in states of matter
Answer:
0.508 mole
Explanation:
NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.
The number of mole present in 78.2 g of CCl₄ can be obtained as follow:
Mass of CCl₄ = 78.2 g
Molar mass of CCl₄ = 12 + (35.5×4)
= 12 + 142
= 154 g/mol
Mole of CCl₄ =?
Mole = mass / molar mass
Mole of CCl₄ = 78.2 / 154
Mole of CCl₄ = 0.508 mole
Therefore, 0.508 mole is present in 78.2 g of CCl₄
to be in kg/mL. What you need to do first is write 22.4 kg/L over 1. Divide this by 1000 because there are 1000 mL per L. Your equation will look like 22.4 kg/L over 1 divided by 1000/1. You end up getting .0224 kg/mL.
Answer:
the answer to your problem is A.Subscript...BRAINLIEST
Answer:
with the proton inside the nucleus
