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bogdanovich [222]
3 years ago
11

Please Easy Chem Question 15 points...

Chemistry
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

Mass of NaOH required= 60 g

Explanation:

Given data:

Mass of NaHCO₃ = 126 g

Mass of NaOH required = ?

Solution:

Chemical equation:

NaOH + CO₂   →   NaHCO₃

Number of moles of NaHCO₃:

Number of moles = mass/ molar mass

Number of moles = 126 g/ 84 g/mol

Number of moles = 1.5 mol

Now we will compare the moles of NaHCO₃ and NaOH.

                   NaHCO₃       :        NaOH

                        1               :            1

                      1.5              :            1.5

Mass of sodium hydroxide:

Mass = number of moles × molar mass

Mass = 1.5 mol × 40 g/mol

Mass = 60 g

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malfutka [58]

The molar mass of gas = 206.36 g/mol

<h3>Further explanation</h3>

In general, the gas equation can be written

\large{\boxed{\bold{PV=nRT}}}

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

mass (m)= 2.89 g

volume(V) = 346 ml = 0.346 L

T = 28.3 C + 273 = 301.3 K

P = 760 mmHg=1 atm

The molar mass (M) :

\tt PV=\dfrac{m}{M}RT\\\\M=\dfrac{mRT}{PV}\\\\M=\dfrac{2.89\times 0.082\times 301.3}{1\times 0.346}\\\\M=206.36~g/mol

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When a 18.0 mL sample of a 0.308 M aqueous hydrofluoric acid solution is titrated with a 0.361 M aqueous sodium hydroxide soluti
sleet_krkn [62]

Answer:

pH = 12.8

Explanation:

HF + NaOH → F⁻ + Na⁺ + H₂O

<em>1 mole of HF reacts with 1 mole of NaOH</em>

<em />

Initial moles of HF and NaOH are:

HF = 0.018L × (0.308mol / L) = 5.544x10⁻³mol HF

NaOH = 0.023L × (0.361mol / L) = 8.303x10⁻³mol NaOH

That means moles of NaOH remains after reaction are:

8.303x10⁻³mol - 5.544x10⁻³mol = <em>2.759x10⁻³moles NaOH</em>

Total volume is 18.0mL + 23.0mL = 41.0mL = 0.0410L

Molar concentration of NaOH is

2.759x10⁻³moles NaOH / 0.0410L = 0.0673M = [OH⁻]

pOH = - log [OH⁻] = 1.17

As pH = 14 - pOH

<em>pH = 12.8</em>

<em></em>

4 0
3 years ago
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