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3 years ago

Please Easy Chem Question 15 points...

Chemistry

1 answer:

HACTEHA [7]3 years ago

4 0

Answer:

Mass of NaOH required= 60 g

Explanation:

Given data:

Mass of NaHCO₃ = 126 g

Mass of NaOH required = ?

Solution:

Chemical equation:

NaOH + CO₂ → NaHCO₃

Number of moles of NaHCO₃:

Number of moles = mass/ molar mass

Number of moles = 126 g/ 84 g/mol

Number of moles = 1.5 mol

Now we will compare the moles of NaHCO₃ and NaOH.

NaHCO₃ : NaOH

1 : 1

1.5 : 1.5

Mass of sodium hydroxide:

Mass = number of moles × molar mass

Mass = 1.5 mol × 40 g/mol

Mass = 60 g

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The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$