Answer:
Number 1 is A (I'm not sure but i think it is) and Number 2 is correct (I think)
Explanation:
88.5% is the correct answer according to my calculations.
Answer:
- 2Al (s) + 3Br₂ (l) → 2AlBr₃(s)
Explanation:
<u>1) Word equation:</u>
- aluminum metal + liquid bromine → aluminum bromide
<u>2) Chemical equation:</u>
- Al (s) + Br₂ (l) → AlBr₃(s)
<u>3) Balanced chemical equation:</u>
- 2Al (s) + 3Br₂ (l) → 2AlBr₃(s)
<u>4) Notes:</u>
- The most common oxidation state of aluminum is +3.
- Bromine has 5 common oxidation states: -1, +1, +3, +5, and +7.
- Since aluminum has a positive oxidation state, bromine must have the negative oxidation state, - 1.
- In the molecular formula the valences (oxidation numbers) are exchanged as subscripts, that is the reason Al has subscript 1 (understood) while Br has subscript 3.
- This is combination or synthesis reaction: two elements combine to form a new compound.
- This is a very exothermic reaction which yields light (sparks) and heat.
- The product, AlBr₃ is a molecular compound (not ionic).
M/s^2, its an acceleration towards an object