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Juli2301 [7.4K]
3 years ago
15

Fill in the term that best completes the statement. Work transfers between objects.

Physics
1 answer:
Otrada [13]3 years ago
3 0

Answer:

<em><u>Energy is the term that best completes the statement.</u></em>

<em><u></u></em>

<em><u>Hope this helps!</u></em>

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What is evaporation? Condensation? Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
krok68 [10]

Answer:

Evaporation is the physical change in which a substance converts from its <u>liquid</u> state to its <u>gaseous</u> state. Condensation is the physical change in which a substance converts from its <u>gaseous</u> state to its <u>liquid</u> state.

Explanation:

Evaporation and condensation are opposite processes to each other. Evaporation changes a liquid to a gas and condensation is the reverse.

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How dose the circulatory systems interact with the digestive systems?
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5. A 10 kg ball is traveling at the same speed as a 1 kg ball. Compared to the 10 kg ball, the 1 kg ball has (2 points)
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What’s the rest of the question or is that it?
4 0
2 years ago
The length of a certain wire is kept same while its radius is doubled. what is the new resistivity of this wire?
anastassius [24]
The text does not specify whether the resistance R of the wire must be kept the same or not: here I assume R must be kept the same.

The relationship between the resistance and the resistivity of a wire is
\rho =  \frac{AR}{L}
where
\rho is the resistivity
A is the cross-sectional area
R is the resistance
L is the wire length

the cross-sectional area is given by
A=\pi r^2
where r is the radius of the wire. Substituting in the previous equation ,we find
\rho =  \frac{\pi r^2 R}{L}

For the new wire, the length L is kept the same (L'=L) while the radius is doubled (r'=2r), so the new resistivity is
\rho' =  \frac{\pi r'^2 R}{L'}= \frac{\pi (2r)^2 R}{L}=4  \frac{\pi r^2 R}{L}   = 4 \rho
Therefore, the new resistivity must be 4 times the original one.
5 0
3 years ago
Read 2 more answers
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AlekseyPX

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Explanation: brainleist pls :)

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3 years ago
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