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LUCKY_DIMON [66]
3 years ago
14

What element is represented by the electron configuration [ar]4s23d8?

Chemistry
1 answer:
beks73 [17]3 years ago
6 0
The answer is Copper

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A substance with a mass of 50.0 g has a temperature change of 40.0
grigory [225]

Answer:

Mass=50.0g

H=670J

change in temperature=40

using. c=h÷m×change in temperature

c=670÷50×40

C=670÷2000

C=0.335jkg-1k-1

7 0
2 years ago
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Two atoms with the same number of protons but a different number of neutrons are
Luda [366]
They are called isotopes.

Example of isotopes are Hydrogen and deuterium.
Hydrogen is 1 proton and 0 neutrons.
Deuterium is 1 proton and 1 neutron
6 0
3 years ago
Find the number of moles in 3.62 x 1024 atoms of helium.
Makovka662 [10]
3.62x10^24/ 6.02x10^23=  6.013 moles to 3dp
8 0
3 years ago
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Balance the equation :
Sati [7]

The balanced equation is 2 AlI 3 ( a q ) + 3 Cl 2 ( g ) → 2 AlCl 3 ( a q ) + 3 I 2 ( g ) .

<u>Explanation:</u>

  • Aluminum has a typical oxidation condition of  3+  , and that of iodine is  1-  .   Along these lines, three iodides can bond with one aluminum. You get  AlI3.  For comparable reasons, aluminum chloride is  AlCl3.  
  • Chlorine and iodine both exist normally as diatomic components, so they are  Cl2(  g  )  also,  I2(  g  ), individually. In spite of the fact that I would anticipate that iodine should be a strong.  

Balancing the equation, we get:  

            2AlI 3(  aq  )  +  3Cl2 (  g  )  →  2AlCl3 (  aq  )   +  3 I 2  (  g  )  

  • Realizing that there were two chlorines on the left, I simply found the basic numerous of 2 and 3 to be 6, and multiplied the  AlCl  3  on the right.  
  • Normally, presently we have two  Al  on the right, so I multiplied the  AlI  3  on the left. Hence, I have 6  I  on the left, and I needed to significantly increase  I 2  on the right.  
  • We should note, however, that aluminum iodide is viciously receptive in water except if it's a hexahydrate. In this way, it's most likely the anhydrous adaptation broke down in water, and the measure of warmth created may clarify why iodine is a vaporous item, and not a strong.
3 0
3 years ago
2-butanone is converted into 3-methyl-3-hexanol using a grignard reagent prepared from 1-bromopropane and magnesium metal in thf
Andre45 [30]

Answer:

Here's what I get.

Explanation:

At the end of the reaction you will have a solution of the alcohol in THF.

The microdistillation procedure will vary, depending on the specific apparatus you are using, but here is a typical procedure.

  • Transfer the solution to a conical vial.
  • Add a boiling stone.
  • Attach a Hickman head (shown below) and condenser.
  • Place the assembly in in the appropriate hole of an aluminium block on top of a hotplate stirrer.
  • Begin stirring and heating at a low level so the THF (bp 63 °C) can distill slowly.
  • Use a Pasteur pipet to withdraw the THF as needed.
  • When all the THF has been removed, raise the temperature of the Al block and distill the alcohol (bp 143 °C).

7 0
3 years ago
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