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Andreyy89
3 years ago
6

A quality control officer is randomly checking the weights of flour bags being filled by an automatic filling machine. Each bag

is advertised as weighing 750 grams. A bag must weigh within 3.2 grams in order to be accepted. What is the range of rejected bags, x, for the bags of flour?
746.8 < x < 753.2

x < 750.0 and x > 753.2

750.0 < x < 753.2

x < 746.8 and x > 753.
Mathematics
1 answer:
Vesna [10]3 years ago
6 0
I think the correct answer from the choices listed above is the last option. The range of the rejected bags, x, for the bags of flour. A bag of flour is said to  weigh within 3.2 grams in order to be accepted. Therefore, it should weigh within 746.8 to 753.2 grams. Outside that range is rejected.
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PilotLPTM [1.2K]

Answer:

  no solution

Step-by-step explanation:

Subtract 7 from both sides of the inequality:

  |x| +7 -7 < 4 -7

  |x| < -3

This has <u>no solution</u>, because an absolute value cannot be negative.

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3 years ago
Using FOIL method. Multiply the terms. (X^2 -7)(x^2 -4)
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Answer:

x^4-11x^2+28

Step-by-step explanation:

  1. Set it up

x^2(x^2-4) -7(x^2-4)

    2. Multiply

x^4-4x^2-7x^2+28

    3. Simplify

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3 years ago
A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a
zaharov [31]

Answer:

a) P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

b) P(X

And we can find this probability uing the normal standard table:

P(z

c) P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(5,1.2)  

Where \mu=5 and \sigma=1.2

We are interested on this probability

P(X>3.5)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability uing the normal standard table:

P(z

Part c

P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

3 0
3 years ago
Simplity (4^-2)^5<br> A.1/4^10<br> B. 4^3<br> C.1/4^3<br> D. 4^10
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Answer:

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Step-by-step explanation:

The given expression is : (4^{-2})^5

We need to simplify the above expression.

We know that, x^{-a}=\dfrac{1}{x^a}

or

(4^{-2})^5=(\dfrac{1}{4^2})^5\\\\=\dfrac{1^5}{(4^2)^5}\\\\\because (x^b)^c=x^{b\times c}\\\\=\dfrac{1}{4^{10}}

So, the simplified form of the given expression is \dfrac{1}{4^{10}}. Hence, the correct option is (A).

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