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Vaselesa [24]
3 years ago
9

What is the difference between vector and scalar ?

Physics
1 answer:
ddd [48]3 years ago
7 0
The easiest, non-technical way to think about it is like this:

-- A scalar is a quantity that has a size but no direction.
Those include temperature, speed, cost, volume, distance, etc.

One number is all there is to know about it, and there's no way you can
add more of the same stuff to it that would cancel both of them out.

-- A vector is a quantity that has a size and also has a direction.
Those include force, displacement, velocity, acceleration, etc.

It takes more than one number to completely describe one of these.
Also, if you combine two of the same vector quantity in different ways,
you can get different results, and they can even cancel each other out.

Here are some examples.  Notice that in each of these examples,
every speed has a direction that goes along with it.  This turns the
scalar speed into a vector velocity.

If you're walking inside a bus, and the bus is driving along the road,
then your velocity along the road is the sum of your walking velocity
inside the bus plus the velocity of the bus along the road.

-- If you're walking north up the middle of the bus at 2 miles per hour
and the bus is driving north along the road at 20 miles per hour, then
your velocity along the road is 22 miles per hour north.

-- If you're walking south towards the back of the bus at 2 miles per hour
and the bus is driving north along the road at 5 miles per hour, then your
velocity along the road is 3 miles per hour north.

-- If you're walking south towards the back of the bus at 2 miles per hour
and the bus is just barely rolling north along the road at 2 miles per hour,
then your velocity along the road is zero.

--  If you're in a big railroad flat-car that's rolling north along the track
at 2 miles per hour, and you walk across the flat-car towards the east
at 2 miles per hour, then your velocity along the ground is 2.818 miles
per hour toward the northeast.
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A carbon resistor is 4 mm long and has a constant cross section of 0.2 mm2. The conductivity of carbon at room temperature is 3
tangare [24]

Answer:

The resistance is found to be 6Ω

The current is found to be 0.66 A

Explanation:

The resistance of a conductor in terms of its dimensions is given as:

R = ρL/A

where,

R = resistance = ?

ρ = resistivity = 3 x 10⁴ Ω.m

L = Length = 4 mm = 0.004 m

A = Cross-sectional area = 0.2 mm² = 0.2 x 10⁻⁶ m²

Therefore,

R = (3 x 10⁴ Ω.m)(0.004 m)/(0.2 x 10⁻⁶ m²)

<u>R = 6 Ω</u>

Now, the potential difference between both ends of the resistor is:

ΔV = 16 V - 12 V = 4 V

Now, from Ohm's Law:

V = IR

I = V/R

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A myopic person (assume no astigmatism) is diagnosed with a far point of 160 cm. What corrective prescription should they be sup
Kazeer [188]

Answer:

The person should use a convex lens of power -0.625 D.

Explanation:

Given that, the far point of the person, with myopic eye, is 160 cm.

It means that the image of an object, which is at infinity, is formed at this point 160 cm distance away from the person's eye.

If the object is infinity, then the object distance, u = -\infty.

Image distance, v = -160 cm.

u and v are taken to be negative because the object and the image of the object are on the side of the eye from where the light is coming.

Let the focal length of the lens which is to be used for the correction of this myopic eye be f, then using lens equation,

\rm \dfrac 1f = \dfrac 1v-\dfrac 1u=\dfrac 1{-160 }-\dfrac1{-\infty}=\dfrac 1{-160}-0=\dfrac 1{-160}.\\\Rightarrow f=-160\ cm.

The negative focal length indicates that the lens should be convex.

The power of the lens is given by

\rm P=\dfrac{1}{f}=\dfrac{1}{-160\ cm }=\dfrac{1}{-1.6\ m}=-0.625\ D.

So, the person should use a convex lens of power -0.625 D.

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