Sharing of 4 electrons between two atoms results in two double bonds. This can be see in the case of oxygen molecule (O2)
Atomic number of O = 8
Electron configuration of O = 1s²2s²2p⁴
Valence electron configuration: 2s²2p⁴
When 2 O atoms combine they share 4 electrons to form 2 double bonds. In addition, there are two lone pairs on each O atom.
Structural formula: O=O
Answer:
The position of my house is a little uphill as compared to the position of my school. The distance I have to travel from my house to school is nearly 2 kilometers. The displacement is in the 2000 m towards the left from my house. The speed of the bus which I usually take is 40 km/ hour.
Answer:
d. 6.0 m
Explanation:
Given;
initial velocity of the car, u = 7.0 m/s
distance traveled by the car, d = 1.5 m
Assuming the car to be decelerating at a constant rate when the brakes were applied;
v² = u² + 2(-a)s
v² = u² - 2as
where;
v is the final velocity of the car when it stops
0 = u² - 2as
2as = u²
a = u² / 2s
a = (7)² / (2 x 1.5)
a = 16.333 m/s
When the velocity is 14 m/s
v² = u² - 2as
0 = u² - 2as
2as = u²
s = u² / 2a
s = (14)² / (2 x 16.333)
s = 6.0 m
Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.
The correct option is d
Answer:
c.![a_m](https://tex.z-dn.net/?f=a_m)
Explanation:
We are given that
Acceleration due to gravity on the moon=![a_m](https://tex.z-dn.net/?f=a_m)
Acceleration due to gravity on the earth=![a_e](https://tex.z-dn.net/?f=a_e)
![g_m=\frac{1}{6}g_e](https://tex.z-dn.net/?f=g_m%3D%5Cfrac%7B1%7D%7B6%7Dg_e)
Net force due to am on an object on moon=![F_{net}=ma_m](https://tex.z-dn.net/?f=F_%7Bnet%7D%3Dma_m)
There is no friction and no drag force and there is no gravity involved
Then, the force acting on an object on earth=![F=ma_e](https://tex.z-dn.net/?f=F%3Dma_e)
(given)
![ma_m=ma_e](https://tex.z-dn.net/?f=ma_m%3Dma_e)
![a_e=a_m](https://tex.z-dn.net/?f=a_e%3Da_m)
Hence, option c is true.