Answer:
E
Explanation:
Using Coulomb's law equation
Force of the charge = k qQ /d²
and E = F/ q
substitute for F
E = ( K Qq/ d² ) / q
q cancel q
E = KQ / d²
so twice the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²
Answer:
x = 50 N
Explanation:
Given that we have a net force, a mass, and acceleration, we can use the fundamental formula for force found in newton's second law which is F = m × a.
Given a mass of 150 kg, and an acceleration 3.0m/s². We can substitute these two values in our formula to calculate the magnitude of these forces or it's net force to identify the unknown force acting on our known force for this situation to work.
_______
F (Net force) = F2 (Second force which we are given) - F1 (First force) = m × a
m (mass which we are given) = 150 kg
a (acceleration which we are given) = 3.0m/s
________
So F = m × a → F2 - F1 = m × a →
500 - F1 = 150 × 3.0 → 500 - F1 = 450 →
-F1 = -50 → F1 = 50
The correct answer is: wavelength =
4562 nm
Explanation:Rydberg's formula is given as:
![\frac{1}{\lambda} = R[ \frac{1}{n_1^2} - \frac{1}{n_2^2} ]](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%20R%5B%20%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20%20-%20%5Cfrac%7B1%7D%7Bn_2%5E2%7D%20%5D%20)
--- (1)
Where
R = Rydberg's constant = 1.096 * 10^7 per meter
= 5
= 7
λ = Wavelength
Plug in the values in (1):
(1)=>
![\frac{1}{\lambda} = (1.096 * 10^7)[ \frac{1}{5^2} - \frac{1}{7^2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%20%281.096%20%2A%2010%5E7%29%5B%20%5Cfrac%7B1%7D%7B5%5E2%7D%20-%20%5Cfrac%7B1%7D%7B7%5E2%7D%20%5D)
![\frac{1}{\lambda} = (1.096 * 10^7)[ 0.04 - 0.020 ] \\ \lambda = \frac{1}{(1.096 * 10^7)[0.020 ]} \\ \lambda = 4562 nm](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%20%281.096%20%2A%2010%5E7%29%5B%200.04%20-%200.020%20%5D%20%5C%5C%20%5Clambda%20%3D%20%20%5Cfrac%7B1%7D%7B%281.096%20%2A%2010%5E7%29%5B0.020%20%5D%7D%20%5C%5C%20%5Clambda%20%3D%204562%20nm)
I would say A is the answer im not sure tho
