1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babunello [35]
2 years ago
5

At an ocean depth of 10.0m, a diver's lung capacity is 2.40L. The air temperature is 32.0°C and the pressure is 101.30 kPa. What

is the volume of the diver's at the same depth, at a temperature of 21.0°C and a pressure of 141.20 kPa?
Physics
1 answer:
Inessa [10]2 years ago
8 0

Answer: The volume of the diver's at the same depth, at a temperature of 21.0°C and a pressure of 141.20 kPa is 1.66 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 101.30 kPa

P_2 = final pressure of gas = 141.20 kPa

V_1 = initial volume of gas = 2.40 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 32.0^0C=(32+273)K=305K

T_2 = final temperature of gas = 21.0^0C=(21+273)K=294K

Now put all the given values in the above equation, we get:

\frac{101.30\times 2.40}{305}=\frac{141.20\times V_2}{294}

V_2=1.66L

The volume of the diver's at the same depth, at a temperature of 21.0°C and a pressure of 141.20 kPa is 1.66 L

You might be interested in
Which of the following effects is produced by the high surface tension of water? Which of the following effects is produced by t
Mashcka [7]

<u>Answer:</u>

<em>A water strider can walk along the surface of earth due to the surface tension of water. </em>

<u>Explanation:</u>

Fluids have a <em>tendency to shrink to minimum possible surface area</em> and this is called surface tension. It usually occurs due to the greater force of cohesion between molecules of same substance when compared to adhesive force between molecules of different substances. Objects with greater densities can float along water surface due to the <em>role played by surface tension. </em>

When insects walk along the water surface they  are pulled down due to gravity. But  the  force of attraction  between the legs of the insect and water molecules is minimal. Thus the surface tension would always tend to maintain the <em>flatness of water overcoming</em> the push by the legs of the strider.  

When the insect’s weight pulls it down , the surface tension pushes it upwards  overcoming this force of gravity. This is how<em> water striders move along the surface of water.  </em>

7 0
3 years ago
How can you use climatograph in a sentence? How can you use ecozone in a sentence?
Sav [38]
Ecozone<span> is the broadest biogeographic division of the Earth's land surface, based on distributional patterns of terrestrial organisms.</span> A climatograph<span> is used to show the precipitation and the temperature of a region.
</span>
5 0
3 years ago
A 50 kg runner runs up a flight of stairs. The runner starts out covering 3 steps every second. At the end the runner stops. Thi
nadezda [96]

To solve the problem it is necessary to take into account the concepts of kinematic equations of motion and the work done by a body.

In the case of work, we know that it is defined by,

W = F * d

Where,

F= Force

d = Distance

The distance in this case is a composition between number of steps and the height. Then,

d=h*N, for h as the height of each step and N number of steps.

On the other hand we have the speed changes, depending on the displacement and acceleration (omitting time)

V_f^2-V_i^2 = 2a\Delta X

Where,

V_f = Final velocity

V_i = Initial Velocity

a = Acceleration

\Delta X = Displacement

PART A) For the particular case of work we know then that,

W = F*d

W = m*g*(h*N)

W = 50*9.8*(0.3*30)

W = 4.41kJ

Therefore the Work to do that activity is 4.41kJ

PART B) To find the acceleration (from which we can later find the time) we start from the previously given equation,

V_f^2-V_i^2 = 2a\Delta X

Here,

V_i = \frac{0.3*3}{1} = 0.90m/s\rightarrow3 steps in one second

v_f = 0

Replacing,

V_f^2-V_i^2 = 2a\Delta X

0-0.9^2=2a(30*0.3)

Re-arrange for a,

a = -\frac{0.9^2}{2*30*0.3}

a = -45*10^{-3}m/s^2

At this point we can calculate the time, which is,

t = \frac{\Delta V}{a}

t = \frac{0-0.9}{-45*10^{-3}}

t = 20s

With time and work we can finally calculate the power

P = \frac{W}{t} = \frac{4.41}{20}

P = 0.2205kW

6 0
3 years ago
An object initially at rest experiences an acceleration
lidiya [134]

Answer:

1.4m/s

Explanation:

Average velocity is the total distance covered divided by the total time taken.

 Average velocity  = \frac{total distance }{time }  

 Total time taken  = 5s + 6s  = 11s

The first distance covered  = velocity x time  = 1.4 x 5 = 7m

     second distance covered  = velocity x time  = 1.4 x 6  = 8.4m

So;

  Average velocity  = \frac{7 + 8.4}{11}    = 1.4m/s

5 0
3 years ago
A 0.2 kg block sliding on a horizontal table slows down from 25 m/s to 20 m/s. How much energy does the block lose due to fricti
Papessa [141]

Answer:

the kinetic energy lost due to friction is 22.5 J

Explanation:

Given;

mass of the block, m = 0.2 kg

initial velocity of the block, u = 25 m/s

final velocity of the block, v = 20 m/s

The kinetic energy lost due to friction is calculated as;

\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 -  \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J

Therefore, the kinetic energy lost due to friction is 22.5 J

7 0
3 years ago
Read 2 more answers
Other questions:
  • A mysterious rocket-propelled object of mass 47.5kg is initially at rest in the middle of the horizontal, frictionless surface o
    8·1 answer
  • The value of efficiency is never 100% or more in practice. why​
    15·1 answer
  • Which part of the ear receives the signal from the cochlea and transmits it to the brain?
    9·2 answers
  • The red rocky planet with polar ice caps is __________.
    7·1 answer
  • How do sound waves travel through a medium?
    15·1 answer
  • Which of the following is a result of the transfer of energy?
    9·2 answers
  • The motion of a free falling body is an example of __________ motion​
    8·1 answer
  • A 9.0 kg potted plant slides down a 25.0º incline with an acceleration of 2.4 m/s2. What is the coefficient of kinetic friction
    11·1 answer
  • Orion Balatik Big Dipper Apparent Brightness Absolute Brightness Polaris Star Trail Malihe Gemini Buwaya 1. Local constellation
    5·1 answer
  • The amount of force applied to an object multiplied by time is
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!