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Snowcat [4.5K]
3 years ago
9

The water-gas shift reaction CO(g)+H2O(g)⇌CO2(g)+H2(g) is used industrially to produce hydrogen. The reaction enthalpy is ΔH∘=−4

1kJ.Part A
To increase the equilibrium yield of hydrogen would you use high or low temperature?
Drag the terms on the left to the appropriate blanks on the right to complete the sentences
high
exothermic
low
endothermic
decreasing
increasing
We would use We would use blanktemperature. For an blankreaction such as this, blanktemperature increases the value of Kand the amount of products at equilibrium. temperature. For an We would use blanktemperature. For an blankreaction such as this, blanktemperature increases the value of Kand the amount of products at equilibrium. reaction such as this, We would use blanktemperature. For an blankreaction such as this, blanktemperature increases the value of Kand the amount of products at equilibrium. temperature increases the value of K and the amount of products at equilibrium.
Part B
Could you increase the equilibrium yield of hydrogen by controlling the pressure of this reaction? If so would high or low pressure favor formation of H2(g)?
Could you increase the equilibrium yield of hydrogen by controlling the pressure of this reaction? If so would high or low pressure favor formation of ?A) Yes. Low pressure would favor formation of H2(g).
B) Yes. High pressure would favor formation of H2(g).
C) No. We cannot increase the equilibrium yield of hydrogen by controlling the pressure of this reaction.
Chemistry
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

The answers are in the explanation

Explanation:

A. For the reaction:

CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g);  ΔH°=−41kJ.

As the reaction is exothermic ( ΔH°<0), you need to use low temperature to increase the equilibrium yield of hydrogen -LeChatelier's principle-.

We would use <em>low </em>temperature. For an <em>exothermic </em>reaction such as this, <em>decreasing </em>temperature increases the value of K and the amount of products at equilibrium.

B.

c. No. We cannot increase the equilibrium yield of hydrogen by controlling the pressure of this reaction.

It is possible to increase the equilibrium yield of reaction by controlling the amount of reactants added. As reactants and products are gases, the pressure of the reaction will not change the amount of reactants or products in the equilibrium.

I hope it helps!

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vladimir1956 [14]

Answer:

B, 2.22×10^22 molecules

Explanation:

Given PV=nRT, n=PV/RT

n=103.7×1.0/8.314×(65+273.15)

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Given n= number of particles/avogadros number

number of particles=n×avogadros number

number of particles = 0.03688...×6.02x10^23

= 2.22×10^22 molecules

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Solution us here,

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here, it looks like I have done wrong.

But all of the answers in option are wrong.

Because, rate of diffusion of any gas is inversely proportional to the square root of its malor mass.

And in the question, gas has higher rate of diffusion than hrdrogen. So it should have molar mass less than hydrogen.

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