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Sliva [168]
3 years ago
5

Two moles of neon gas enclosed in a constant volume system receive 4250 J of heat. If the gas was initially at 293 K, what is th

e final temperature of the neon
Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
3 0

Answer:

<u><em>=355.5K</em></u>

Explanation:

Specific heat, Q = mcΔT

where

  • Q= 4250J
  • ΔT= change in temp = final temp - initial temp
  • c = specific heat capacity = 1.7
  • m = mass of substance in grams

[1 mole of Ne = 20g; 2 moles of Ne = 2 × 20 = 40g]

4250 = 40 × 1.7 × (final - 293K)

final - 293k = 4250 / ( 40 × 1.7)

Final temp = 62.5 + 293

<em>=355.5K</em>

I hope this steps are simple to follow and understand.

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