Explanation:
Formula to determine the critical crack is as follows.

= 1,
= 24.1
[/tex]\sigma_{y}[/tex] = 570
and, 
= 427.5
Hence, we will calculate the critical crack length as follows.
a = 
= 
= 
Therefore, largest size is as follows.
Largest size = 2a
= 
= 
Thus, we can conclude that the critical crack length for a through crack contained within the given plate is
.
Answer:
a) At x=14 the slope will be given by:
.
b) Then, the angle between the line and the pole will be:

where
is the angle between the tangent to the catenary and the x-axis.
Explanation:
The catenary has the following general form:

a) The slope at any point will be given by the derivative of y.

At x=14:
.
b) The angle between the tangent to the catenary and the x-axis at a given point will be given by:
⇒ 
Then, the angle between the line and the pole will be:
.
v initial = 0m/s
v final = 40m/s
t = 5s
d = ?
The kinematic equation which relates these quantities:
d = 1/2(vinitial + vfinal)t
d = 0.5(0+40)(5)
d = 100m
Answer:
F = 0.075 N
Explanation:
given,
diameter of ping pong ball = 2.55 cm
average density of the ball = 0.116 g/cm³
Force require to hold the ball completely submerged= ?
Volume of the ball


V = 8.63 cm³
density of water = 1 g/cm³
force required to keep the ball submerged is equal to


F = 7.63 x 9.8 x 10⁻³
F = 0.075 N
Force required to keep the ball inside the water is equal to 0.075 N