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marissa [1.9K]
3 years ago
13

A 1200 kg car traveling north at 10 m/s is rear-ended by a 2000 kg truck traveling at 30 m/s. What is the total momentum before

and after the collision?
Physics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

The total momentum before and after collision is 72000 kg-m/s.

Explanation:

Given that,

Mass of car = 1200 kg

Velocity of car = 10 m/s

Mass of truck = 2000 kg

Velocity of truck = 30 m/s

Using conservation of momentum

The total momentum before the collision is equal to the total momentum after collision.

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V

Where, m_{1}=mass of car

v_{1} =velocity of car

m_{1}=mass of truck

v_{1} =velocity of truck

Put the value into the formula

1200\times10+2000\times30=(1200+2000)V

V=\dfrac{1200\times10+2000\times30}{(1200+2000)}

V = 22.5\ m/s

Now, The total momentum before collision is

P=m_{1}v_{1}+m_{2}v_{2}

P=1200\times10+2000\times30

P=72000\ kg-m/s

The total momentum after collision is

P=(m_{1}+m_{2})v_{2}

P=(1200+2000)\times22.5

P= 72000 kg-m/s

Hence, The total momentum before and after collision is 72000 kg-m/s.

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