Ask question

Ask question

All categories

3 years ago

13

A 1200 kg car traveling north at 10 m/s is rear-ended by a 2000 kg truck traveling at 30 m/s. What is the total momentum before

and after the collision?

1 answer:

tino4ka555 [31]3 years ago

4 0

Answer:

The total momentum before and after collision is 72000 kg-m/s.

Explanation:

Given that,

Mass of car = 1200 kg

Velocity of car = 10 m/s

Mass of truck = 2000 kg

Velocity of truck = 30 m/s

Using conservation of momentum

The total momentum before the collision is equal to the total momentum after collision.

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V$

Where, $m_{1}$ =mass of car

$v_{1}$ =velocity of car

$m_{1}$ =mass of truck

$v_{1}$ =velocity of truck

Put the value into the formula

$1200\times10+2000\times30=(1200+2000)V$

$V=\dfrac{1200\times10+2000\times30}{(1200+2000)}$

$V = 22.5\ m/s$

Now, The total momentum before collision is

$P=m_{1}v_{1}+m_{2}v_{2}$

$P=1200\times10+2000\times30$

$P=72000\ kg-m/s$

The total momentum after collision is

$P=(m_{1}+m_{2})v_{2}$

$P=(1200+2000)\times22.5$

$P= 72000 kg-m/s$

Hence, The total momentum before and after collision is 72000 kg-m/s.

You might be interested in

What is the force on a 250 kg elevator that is falling freely at 9.8 m/sec2?

Viefleur [7K]

Answer:

Since it is falling freely, the only force on it is its weight, w.

w = m × g = 250 kg × 9.8 m/s^2 = 2450 Newton/N

6 0

3 years ago

Read 2 more answers

As you learned in Part B, a non-burning helium core surrounded by a shell of hydrogen-burning gas characterizes the subgiant sta

Gennadij [26K]

Answer:

E- The star becomes a red giant (LATEST STAGE)

F- The surface of the star becomes brighter and cooler

C- Pressure from the star's hydrogen-burning shell causes the non burning envelope to expand

A- The shell of hydrogen surrounding the star's nonburning helium core ignites.

D- The star's non burning helium core starts to contract and heat up

B- Pressure in the star's core decreases (EARLIEST STAGE)

(A star moves away from the main sequence once its core runs out of hydrogen to fuse into helium. The energy once supplied by hydrogen burning reduces and the core starts to compress under the force of gravity. This contraction allows the core and surrounding layers to heat up. Finally, the hydrogen shell around the core becomes hot enough to ignite hydrogen burning.

6 0

3 years ago

Si el cuerpo no se mueve halle T

Aleks [24]

Well sorry but this is the wrong language.

3 0

2 years ago

Read 2 more answers

Unpolarized light with intensity S is incident on a series of polarizing sheets. The first sheet has its transmission axis orien

jeka94

Answer:

Explanation:

Given

Initial Intensity of light is S

when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.

When it is passed through a second Polarizer with its transmission axis $\theat =45^{\circ}$

$S_1=S_0\cos ^2\theta$

here $S_0=\frac{S}{2}$

$S_1=\frac{S}{2}\times \frac{1}{(\sqrt{2})^2}$

$S_1=\frac{S}{4}$

When it is passed through third Polarizer with its axis $90^{\circ}$ to first but $\theta =45^{\circ}$ to second thus $S_2$

$S_2=S_0\cos ^2\theta$

$S_2=\frac{S}{4}\times \frac{1}{2}$

$S_2=\frac{S}{8}$

When middle sheet is absent then Final Intensity will be zero

3 0

3 years ago

A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of

Katen [24]

Answer:

S = V t where S is the horizontal distance traveled

1/2 g t^2 = H where H is the vertical distance traveled

t^2 = 2 H / g

V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations

tan theta = H / S

V^2 = S g / (2 tan theta)

Using S = L cos theta

V^2 = L g cos theta / (2 tan theta)

Giving V in terms of L and theta

7 0

2 years ago