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3 years ago

A mixture of nitrogen and hydrogen gases, at a temperature of 500

Chemistry

1 answer:

Nesterboy [21]3 years ago

6 0

Answer:

0.7589 mol/L ≅ 0.76 mol/L.

Explanation:

For the equilibrium mixture:

N₂(g) + 3H₂(g) ⇄ 2NH₃(g),

Kc = [NH₃]²/[N₂][H₂]³

At 500 K, V = 6.0 dm³ = 6.0 L:

Kc = 6.0 x 10⁻²,

[N₂] = (7.2 mol)/(6.0 L) = 1.2 mol/L, [H₂] = (12.0 mol)/(6.0 L) = 2.0 mol/L.

∴ [NH₃]² = (Kc)[N₂][H₂]³ = (6.0 x 10⁻²)(1.2 mol/L)(2.0 mol/L)³ = 0.576.

∴ [NH₃] = √(0.576) = 0.7589 mol/L ≅ 0.76 mol/L.

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Explanation:

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