Groups of four for the group of 288 and groups of five for the group of 360
Im pretty sure D bonded pair of electrons is the answer
<span>ow far does the first car go in the 2 hours head start it gets?
Now, at t = 2 hours, both cars are moving. How much faster is the second car than the first car? How long will it take to recover the head start? You can determine this by dividing the head start by the difference in the two speeds. If car 1 has a 20 mile head start, and car 2 is 5 mph faster, then it will take 20/5 = 4 hours to catch up.
</span>You could also write two equations, one for each car, showing how far they have gone in a variable amount of time. Set the two equations equal to each other and solve for the value of the time. Note that the second car's equation will use (t-2) for the time, because it doesn't start driving until t = 2.
The computation shows that the difference in depth is 16 feet
<h3>How to calculate the value?</h3>
From the information, in January, it measured 6 ft deep, or |−6|, and in July, it was -22.
Therefore the difference between the depth will be:
= -6 - (-22)
= -6 + 22
= 16
Therefore, the difference in depth is 16 feet
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