A melting point of a substance is a point at which the sample or substance start converting in liquid. For most substances, melting and freezing points are approximately equal. For example, the melting point and freezing point of mercury is 234.32 kelvins (−38.83 °C or −37.89 °F). Hope this helped!! :)
The volume of 0.555M KNO3 solution would contain 12.5 g of solute iss 223 mL.
<h3>What is the relationship between mass of solute and concentration of solution?</h3>
The mass of solute in a given volume of solution is related by the formula below:
- Molarity = mass/(molar mass * volume)
Therefore, volume of solution is given by:
Volume = Mass /molarity * molar mass
Molar mass of KNO₃ = 101 g/mol
Volume = 12.5/(0.555 * 101)
Volume = 0.223 L or 223 mL
In conclusion, the volume of the solution is obtained from the molarity of solution as well as mass and molar mass of solute.
Learn more about molarity and volume at: brainly.com/question/26873446
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Answer:
CO(g) + 2H₂(g) → CH₃OH(l)
Explanation:
Carbon monoxide has molecular formula CO, molecular hydrogen has formula H₂, and methanol is CH₃OH.
The reactants are CO and H₂ and the product CH₃OH:
CO(g) + H₂(g) → CH₃OH(l)
To balance the equation, the elements must have the same amount on each side. C and O are balanced, but there is 4H in the product and only 2 in the reactant, so we multiply H₂ for 2:
CO(g) + 2H₂(g) → CH₃OH(l)
And the equation is balanced.
Answer:
0.004522 moles of hydrogen peroxide molecules are present.
Explanation:
Mass by mass percentage of hydrogen peroxide solution = w/w% = 3%
Mass of the solution , m= 5.125 g
Mass of the hydrogen peroxide = x
![w/w\% = \frac{x}{m}\times 100](https://tex.z-dn.net/?f=w%2Fw%5C%25%20%3D%20%5Cfrac%7Bx%7D%7Bm%7D%5Ctimes%20100)
![3\%=\frac{x}{5.125 g}\times 100](https://tex.z-dn.net/?f=3%5C%25%3D%5Cfrac%7Bx%7D%7B5.125%20g%7D%5Ctimes%20100)
![x=\frac{3\times 5.125 g}{100}=0.15375 g](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B3%5Ctimes%205.125%20g%7D%7B100%7D%3D0.15375%20g)
Mass of hydregn pervade in the solution = 0.15375 g
Moles of hydregn pervade in the solution :
![=\fraC{ 0.15375 g}{34 g/mol}=0.004522 mol](https://tex.z-dn.net/?f=%3D%5CfraC%7B%200.15375%20g%7D%7B34%20g%2Fmol%7D%3D0.004522%20mol)
0.004522 moles of hydrogen peroxide molecules are present.