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4 years ago

When selecting small wares to use in the kitchen, a manager must be sure the small wares are durable, easy to clean, safe, and ?

Chemistry

1 answer:

Ilia_Sergeevich [38]4 years ago

8 0

Answer:

Non-reactors

Explanation:

Kitchen wares should preferably be non-reactors to prevent them from reactiong with food.

Reactions between food substances and wares lead to production of untested and unsecure reaction results.

The production of this predictably hazardous results may result to food poisoning thereby threatening human life.

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Nai(aq)+hg2(no3)2(aq)→ express your answer as a chemical equation. identify all of the phases in your answer. enter noreaction i

Komok [63]

Balanced chemial equation:

2NaI(aq)+Hg2(NO3)2(aq) →Hg2 I2 (s) + 2 NaNO3 (aq)

You can see it better if I use latex:

$2NaI(aq)+Hg_2(NO_3)_2(aq) =Hg_2 I_2 (s) + 2 NaNO_3 (aq)$

As per the phases this is the interpretation:

The symbols (aq) stands for aquous meaning that the compound is dissolved in water.

The symbol (s) stands for solid, meaning tha the compound precipitate and is not dissolved in water.

7 0

4 years ago

What are the eleven elements that are gas freezing?

kenny6666 [7]

hydrogen, helium, oxygen, nitrogen, argon, neon, fluorine, chlorine, krypton, xenon and radon i believe >__< not in any order ahaha

4 0

3 years ago

Read 2 more answers

5. 1.00 mol HNO3 is treated with 4.47 g of magnesium. Calculate the number of moles of

ruslelena [56]

Answer:

The balanced equation is:

2 HNO3 + Mg ---> Mg(NO3)2 + H2

From the equation, we can see that we need twice the moles of HNO3 than the moles of Mg

Moles of Mg:

Molar mass of Mg = 24 g/mol

Moles = Given mass / Molar Mass

Moles of Mg = 4.47 / 24 = 0.18 moles (approx)

Hence, 2(moles of Mg) = 0.36 moles of HNO3 will be consumed

Number of moles of HNO3 after the reaction is finished is the number of unreacted moles of HNO3

Unreacted moles of HNO3 = Total Moles - Moles consumed

Unreacted moles of HNO3 = 0.64 moles (approx)

Since we approximated the value of moles of Mg, the value of remaining moles of HNO3 will also be approximate

From the given options, we can see that 0.632 moles is the closest value to our answer

Therefore, 0.632 moles will remain after the reaction

3 0

4 years ago

A student sets up the following equation to convert a measurement. (The stands for a number the student is going to calculate.)

Crank

Answer:

0.090 J/(mmol·°C) × (1000 mmol/mole × 1 kJ/(1000 J)) = 0.090 kJ/mole

Explanation:

The unit of conversion from kilo-Joules to Joules is given as follows;

1000 Joules = 1 kilo-Joule

The unit of conversion from milimoles to moles is given as follows;

1000 milimoles = 1 Mole

Therefore, we have

The value of the given expression is 0.090 J/(mmol·°C) × 1000 mmol/mole × 1 kJ/(1000 J) = 0.090 kJ/mole

0.090 J/milimole = 0.09 kJ/mole.

3 0

3 years ago

Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca

lina2011 [118]

Answer: The above reaction is non-spontaneous.

Explanation:

For the given chemical reaction:

$Ni^{2+}(aq.)+2Fe^{2+}(aq.)\rightarrow 2Fe^{3+}(aq.)+Ni(s)$

Here, nickel is getting reduced because it is gaining electrons and iron is getting oxidized because it is loosing electrons.

We know that:

$E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Ni^{2+}/Ni)}=-0.23V$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=-0.23-0.77=-1.0V$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

As, the standard electrode potential of the cell is coming out to be negative for the above cell. Thus, the standard Gibbs free energy change of the reaction will become positive making the reaction non-spontaneous.

Hence, the above reaction is non-spontaneous.

3 0

3 years ago