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Elina [12.6K]
3 years ago
9

Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate t

he mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.
Physics
2 answers:
KonstantinChe [14]3 years ago
8 0

By definition, the density is given by:

D = \frac{m}{V}

Where,

m: Helium mass

V: helium volume

Clearing the mass we have:

m = VD

Transforming the volume to milliliters we have:

V = (6.3) * (1000) = 6300 mL

Then, replacing values:

m = (6300) * (1.79 * 10 ^ {-4})\\m = 1.1277 g

Answer:

The mass of helium that would take to fill the balloon is:

m = 1.1277 g

Phantasy [73]3 years ago
8 0

Answer:

The correct answer is 1.1 grams.

Carlosego failed to round it, sorry for his mistake.

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<h3>Briefing:</h3>

Hydrogen has a spectral line at = 116nm=116×10⁻⁹m

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Now, from the Hubble's law

V=(\Delta \lambda / \lambda)×C

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Δλ = Change in wavelength = 116 - 107= 9nm=9×10⁻⁹m

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C is the speed of the light=3×10⁸m/s

on substituting the respective values, we get

V=(9/116)×3×10⁸=23275862.069×10⁵m/s

V=2.3275862×10¹²km/s.

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The relationship between electric and magnetic field at a given peak electric field is given as;

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