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Elina [12.6K]
3 years ago
9

Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate t

he mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.
Physics
2 answers:
KonstantinChe [14]3 years ago
8 0

By definition, the density is given by:

D = \frac{m}{V}

Where,

m: Helium mass

V: helium volume

Clearing the mass we have:

m = VD

Transforming the volume to milliliters we have:

V = (6.3) * (1000) = 6300 mL

Then, replacing values:

m = (6300) * (1.79 * 10 ^ {-4})\\m = 1.1277 g

Answer:

The mass of helium that would take to fill the balloon is:

m = 1.1277 g

Phantasy [73]3 years ago
8 0

Answer:

The correct answer is 1.1 grams.

Carlosego failed to round it, sorry for his mistake.

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Answer:

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Explanation:

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To find the time, we would use the following formula;

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Making time, t the subject of formula, we have;

t = \frac {m(v - u)}{F}

Substituting into the formula, we have;

t = \frac {50(8 - 0)}{200}

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A sample of carbon dioxide (C°p,m = 37.11 J K−1 mol−1) of mass 2.80 g at 27°C is allowed to expand reversibly and adiabatically
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Answer:

182 to 3 s.f

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