Question

Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate the mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.

Answer 1

By definition, the density is given by:

$D = \frac{m}{V}$

Where,

m: Helium mass

V: helium volume

Clearing the mass we have:

$m = VD$

Transforming the volume to milliliters we have:

$V = (6.3) * (1000) = 6300 mL$

Then, replacing values:

$m = (6300) * (1.79 * 10 ^ {-4})\\m = 1.1277 g$

Answer:

The mass of helium that would take to fill the balloon is:

$m = 1.1277 g$

Answer 2

Answer:

The correct answer is 1.1 grams.

Carlosego failed to round it, sorry for his mistake.