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3 years ago

9

Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate t

he mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.

2 answers:

KonstantinChe [14]3 years ago

8 0

By definition, the density is given by:

$D = \frac{m}{V}$

Where,

m: Helium mass

V: helium volume

Clearing the mass we have:

$m = VD$

Transforming the volume to milliliters we have:

$V = (6.3) * (1000) = 6300 mL$

Then, replacing values:

$m = (6300) * (1.79 * 10 ^ {-4})\\m = 1.1277 g$

Answer:

The mass of helium that would take to fill the balloon is:

$m = 1.1277 g$

Phantasy [73]3 years ago

8 0

Answer:

The correct answer is 1.1 grams.

Carlosego failed to round it, sorry for his mistake.

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Power can be defined as the rate at which work is accomplished.

Option D is the correct answer.

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sveticcg [70]

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388.97 nm

Explanation:

The computation of the wavelength of this light in benzene is shown below:

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And, the wavelength of water is 438 nm

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Now placing these values to the above formula

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Answer:

B can take 0.64 sec for the longest nap .

Explanation:

Given that,

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$s=ut+\dfrac{1}{2}at_{A}^2$

Put the value in the equation

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$s=ut+\dfrac{1}{2}at_{B}^2$

Put the value in the equation

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Answer:

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