I think the correct answer from the choices listed above is option A. A high frequency wave is a wave with a low level of energy and a high pitch. Frequency is the number of waves passing per second of time. Hope this answers the question.
Recuerda que distancia=velocidad x tiempo (

). vamos a llamar

a la distancia que reccore el primer bus, y

la distancia que recoore el segundo. Los se econtraran cuando la ditancia recorrida por cada bus sea la misma, es decir

.
Ahora sabemos que la velocidad del primer bus es 30 km/h y su tiempo es

; en cuanto al segundo bus, su velocidad es 45 km/h y como sale 2 horas mas tarde su tiempo será

. Ahora podemos reemplazar los valores en nuestra ecuación de de distanica para hallar el tiempo:





Los buses se encontraran en 6 horas, 4 horas después de haber salido el segundo bus. Ahora para hallar la distancia a la que los buses estaran de <span>san vicente del caguan solo necesitaremos reemplazar la el tiempo en nuestra equación de distancia para el primer bus:
</span>


<span>
En el punto de encuentro los buses estarán a 180 km de San Vicente del Caguan.</span>
The tilt of Earth's axis hope this helps
Answer:
toward the ceiling
Explanation:
In order to determine the direction of the magnetic force on the charge, we should use the right-hand rule. Putting the thumb, the index finger and the middle finger of the right hand perpendicular to each other, we have: (for a positive charge)
- The index finger corresponds to the direction of motion of the charge (in this case, toward north)
- The middle finger corresponds to the direction of the magnetic field (in this case, towards west)
- The thumb will give us the direction of the magnetic force --> in this case, the thumb points towards the ceiling, so the direction of the magnetic force is towards the ceiling.
Answer:
10 days
Explanation:
The half-life of a radioactive sample is the time taken for half of the sample to decay.
In the diagram, the half-life corresponds to the time after which the % of cobalt-57 has halved. We can observe the following:
At t=10 days, the % of Co remaining is approximately 45%
At t=20 days, the % of Co remaining is approximately 22%
This means that the sample of cobalt-57 has halved in 10 days, so the half-life of cobalt-57 is 10 days.