The volume of chlorine required is 7.71 L.
The reaction between phosphorus and chlorine is:
2P + 5Cl₂→ 5PCl₅
Therefore, 2 moles of P requires 5 moles of chlorine to react with it.
Given mass of P =3.39 g
Molar mass of P=30.97 g/mol
No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles
2 moles of P requires 5 moles of chlorine
0.109 moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine
According to ideal gas equation
PV=nRT
2.04 x V = 0.2725 x 0.0821 x 703
V = 0.2725 x 0.0821 x 703 / 2.04
V = 7.71L
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Aluminum is light and is quite unreactive it is malleable and strong too.
Answer:
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Explanation:
where? what is the question?
Answer:
D. when the number of moles of acid is exactly equal to the number of moles of base.
Explanation:
<em>Regarding options A. and E</em>., pKa and pKb would only be taken into consideration if the titrations were of <em>weak</em> acids and bases. However it is possible to have a titration of monoprotic acids and bases with strong acids and bases.
Another way of looking at the answer is identifying <em>which one best describes the equivalence point</em>.
