Answer:
47.5kJ
Explanation:
Before climbing the cliff
At 2.
URGENT
2 answers:
You might be interested in
Answer:
For this ideal Rankine cycle:
A) The rate of heat addition into the cycle Qh is 3214.59KJ/Kg.
B) The thermal efficiency of the system εt=0.4354.
C) The rate of heat rejection from the cycle Qc is 1833.32KJ/Kg.
D) The back work ratio is 0.013
Explanation:
To solve the ideal Rankine cycle we have to determinate the thermodynamic information of each point of the cycle. We will use a water thermodynamic properties table. In an ideal Rankine cycle, the process in the turbine and the pump must be isentropic. Therefore S₃=S₄ and S₁=S₂.
We will start with the point 3:
P₃=18000KPa T₃=550ºc ⇒ h₃=3416.12 KJ/Kg S₃=6.40690 KJ/Kg
Point 4:
P₄=9KPa S₄=S₃ ⇒ h₄=2016.60 (x₄=0.7645 is wet steam)
Point 1:
P₁=P₄ in the endpoint of the steam curve. ⇒ h₁= 193.28KJ/Kg S₁=0.62235KJ/Kg x₁=0
Point 2:
P₂=P₃ and S₂=S₁ ⇒ h₂=201.53KJ/Kg
With this information we can obtain the heat rates, the turbine, and the pump work:
We can answer the questions with this data:
A)
B)
C)
D)
Angular frequency of pendulum is given by
for both pendulum we have
For other pendulum
now we have relate angular frequency given as
[tex\omega_1 - \omega_2 = 3.13 - 2.98 = 0.15 rad/s[/tex]
now time taken to become in phase again is given as
now number of oscillations complete in above time